Answer:
It is true that earth was once covered with oceans and little dry land.
Explanation:
Over the course of around four billion years, the Earth's oceans have lost about a quarter of their original mass. Today the atmosphere is rich in oxygen, which reacts with both hydrogen and deuterium to recreate water, which falls back to the Earth's surface. So the vast bulk of the water on Earth is held in a closed system that prevents the planet from gradually drying out. According to the researchers, the continents emerged relatively suddenly from an ocean that covered 95 percent of the Earth's surface. The appearance of large masses of dry land would have caused more extreme weather, changes in ocean currents and the emergence of proper seasons. In turn, these environmental changes may have led to rise in atmospheric oxygen that enabled the explosion of new life forms around 500 million years ago.
Answer:
1.) 13 g C₄H₁₀
2.) 41 g CO₂
Explanation:
To find the mass of propane (C₄H₁₀) and carbon dioxide (CO₂), you need to (1) convert mass O₂ to moles O₂ (via molar mass), then (2) convert moles O₂ to moles C₄H₁₀/CO₂ (via mole-to-mole ratio from equation coefficients), and then (3) convert moles C₄H₁₀/CO₂ to mass C₄H₁₀/CO₂ (via molar mass). It is important to arrange the ratios in a way that allows for the cancellation of units. The final answers should have 2 sig figs to match the sig figs of the given value.
Molar Mass (C₄H₁₀): 4(12.011 g/mol) + 10(1.008 g/mol)
Molar Mass (C₄H₁₀): 58.124 g/mol
Molar Mass (CO₂): 12.011 g/mol + 2(15.998 g/mol)
Molar Mass (CO₂): 44.007 g/mol
Molar Mass (O₂): 2(15.998 g/mol)
Molar Mass (O₂): 31.996 g/mol
2 C₄H₁₀ + 13 O₂ ----> 8 CO₂ + 10 H₂O
48 g O₂ 1 mole 2 moles C₄H₁₀ 58.124 g
--------------- x ----------------- x -------------------------- x ------------------ =
31.996 g 13 moles O₂ 1 mole
= 13 g C₄H₁₀
48 g O₂ 1 mole 8 moles CO₂ 44.007 g
--------------- x ----------------- x -------------------------- x ------------------ =
31.996 g 13 moles O₂ 1 mole
= 41 g CO₂
<u>Answer:</u> The mass of ice is ![2.39\times 10^{22}g](https://tex.z-dn.net/?f=2.39%5Ctimes%2010%5E%7B22%7Dg)
<u>Explanation:</u>
We are given:
Area of Antarctica =
(Conversion factor:
)
Height of Antarctica with ice = 7500 ft.
Height of Antarctica without ice = 1500 ft.
Height of ice = 7500 - 1500 = 6000 ft =
(Conversion factor: 1 ft = 30.48 cm)
To calculate mass of ice, we use the equation:
![\text{Density of a substance}=\frac{\text{Mass of a substance}}{\text{Volume of a substance}}](https://tex.z-dn.net/?f=%5Ctext%7BDensity%20of%20a%20substance%7D%3D%5Cfrac%7B%5Ctext%7BMass%20of%20a%20substance%7D%7D%7B%5Ctext%7BVolume%20of%20a%20substance%7D%7D)
We are given:
Density of ice = ![0.917g/cm^3](https://tex.z-dn.net/?f=0.917g%2Fcm%5E3)
Volume of ice = Area × Height of ice = ![142.45\times 10^{15}cm^2\times 182.88\times 10^3cm=26051.26\times 10^{18}cm^3](https://tex.z-dn.net/?f=142.45%5Ctimes%2010%5E%7B15%7Dcm%5E2%5Ctimes%20182.88%5Ctimes%2010%5E3cm%3D26051.26%5Ctimes%2010%5E%7B18%7Dcm%5E3)
Putting values in above equation, we get:
![0.917g/cm^3=\frac{\text{Mass of ice}}{26051.26\times 10^{18}cm^3}\\\\\text{Mass of ice}=(0.917g/cm^3\times 26051.26\times 10^{18}cm^3=2.39\times 10^{22}g](https://tex.z-dn.net/?f=0.917g%2Fcm%5E3%3D%5Cfrac%7B%5Ctext%7BMass%20of%20ice%7D%7D%7B26051.26%5Ctimes%2010%5E%7B18%7Dcm%5E3%7D%5C%5C%5C%5C%5Ctext%7BMass%20of%20ice%7D%3D%280.917g%2Fcm%5E3%5Ctimes%2026051.26%5Ctimes%2010%5E%7B18%7Dcm%5E3%3D2.39%5Ctimes%2010%5E%7B22%7Dg)
Hence, the mass of ice is ![2.39\times 10^{22}g](https://tex.z-dn.net/?f=2.39%5Ctimes%2010%5E%7B22%7Dg)
ELETRICK probably wondering why metal shocks (psst why does wires charge phones)
Answer:
42.38875878%
Explanation:
i divided 4.27 g from 1.81g using a percentage calculator but im not sure if its correct