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lidiya [134]
3 years ago
11

For the reaction co(g)+h2o(g)⇌h2(g)+co2(g), k= 4.24 at 800 k what can be said about this reaction at this temperature?

Chemistry
2 answers:
Amanda [17]3 years ago
8 0

The question has missing information.

The options are given below.

a.The equilibrium lies far to the right

b. The reaction will proceed very slowly

c. The reaction contains significant amounts of products and reactants at equilibrium.

d. The equilibrium lies far to the left

Answer : The correct answer is option c: The reaction contains significant amounts of products and reactants at equilibrium.

Explanation :

Option a is not correct because for equilibrium to lie far to the right, we need a large value of keq ( Keq >>> 1 ), but the keq value is small.

option b is also not correct because in order to predict the speed of the reaction, we need more information. The speed of the reaction cannot be predicted using Keq value.

Option d is not correct because for Keq to lie far to the left, it has to be very very small. ( Keq <<< 1)

The value of equilibrium constant is given as 4.24. This value is very near to 1.

Equilibrium constant for this reaction is calculated as

Keq = \frac{[H_{2}] [CO_{2}]}{[H_{2}O][CO]}

When Keq = 1, [H_{2}] [CO_{2}  ] = [CO] [H_{2}O]

That means concentrations of products and reactants are equal.

Since the keq value for our reaction is very close to 1, we can say that , there are significant amounts of reactants and products at equilibrium.

Therefore option C is the correct option.

MariettaO [177]3 years ago
3 0
Idk im tryin to find that answer mans not hot 
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6. Which group of compounds is described as insoluble?
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The acid-dissociation constant for benzoic acid (C6H5COOH) is 6.3×10−5. Calculate the equilibrium concentration of H3O+ in the s
raketka [301]

Answer : The equilibrium concentration of H_3O^+ in the solution is, 2.1\times 10^{-3}M

Explanation :

The dissociation of acid reaction is:

                       C_6H_5COOH+H_2O\rightarrow H_3O^++C_6H_5COO^-

Initial conc.        c                                 0                0

At eqm.             c-x                                 x                x

Given:

c = 7.0\times 10^{-2}M

K_a=6.3\times 10^{-5}

The expression of dissociation constant of acid is:

K_a=\frac{[H_3O^+][C_6H_5COO^-]}{[C_6H_5COOH]}

K_a=\frac{(x)\times (x)}{(c-x)}

Now put all the given values in this expression, we get:

6.3\times 10^{-5}=\frac{(x)\times (x)}{[(7.0\times 10^{-2})-x]}

x=2.1\times 10^{-3}M

Thus, the equilibrium concentration of H_3O^+ in the solution is, 2.1\times 10^{-3}M

4 0
3 years ago
How many moles of oxygen are required to produce 37.15 g CO2? 37.15 g CO2 = mol O2
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Answer:

0.84 moles of oxygen are required.

Explanation:

Given data:

Mass of CO₂ produced = 37.15 g

Number of moles of oxygen = ?

Solution:

Chemical equation:

C + O₂     →     CO₂

Number of moles of  CO₂:

Number of moles = mass/molar mass

Number of moles = 37.15 g/ 44 g/mol

Number of moles = 0.84 mol

Now we will compare the moles of oxygen and carbon dioxide.

                          CO₂         :       O₂  

                              1           :         1

                            0.84       :       0.84

0.84 moles of oxygen are required.

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3 years ago
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