Mass of the compound = 205 g
Molar Mass of compound = ((24) + (2 * 32) + (3 * 16))
= 136 g / mol
∴ # mols in 205g =
= 1.507 mol
Would it make a difference if calcium bromide solution, cabr2, were used rather than sodium bromide solution?
1 answer:
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Mass of the compound = 205 g
Molar Mass of compound = ((24) + (2 * 32) + (3 * 16))
= 136 g / mol
∴ # mols in 205g =
= 1.507 mol