Question

A student wants to prepare a solution of cobalt(II) fluoride with a known molarity.

Answer 1

Answer:

$\large \boxed{\text{1.52 g}}$

Explanation:

1. Calculate the moles of CoF₂ needed

$n = \text{0.100 L} \times \dfrac{\text{0.157 mol}}{\text{1 L}} = \text{0.0157 mol}$

2. Calculate the mass of CoF₂

$m = \text{0.0157 mol} \times \dfrac{\text{96.93 g}}{\text{1 mol}} = \text{1.52 g}\\\\\text{ The student must measure out \large \boxed{\textbf{1.52 g}} of cobalt(II) fluoride}$