Answer:2H₂+ O₂→ 2H₂O the reactants are 2H₂ and O₂ ... if the theoretical yield is 95 g of water after the chemical reaction you may have only 45g of water
i think
Explanation:
<span>A mid-ocean ridge is a mountain rage under the water. It is formed due to plate tectonics. The shifting of the plates lifts up the floor of the ocean. When convection currents happen they raise the mantle that is located beneath the oceans crust and it creates magma where the two tectonic plates meet.</span>
All acids only conduct electric current when they are dissolved in water, because when they are in an aqueous medium, they undergo ionization, i.e. release <span>ions.</span><span>
HCl --> H</span>⁺ + Cl⁻
The bases also conduct electric current in solution, because the Ionic dissociation sufferers (release the existing ions in the formula) and molecular ionization, suffer the reacting with water and releasing ions.
NaOH ---> Na⁺ + OH⁻
hope this helps!
Answer:
533.33 mg quinine
Explanation:
First we<u> calculate the concentration of the diluted sample</u>, using the values obtained by the standard:
- 288 * 100 ppm / 180 = 160 ppm
Now we use the dilution factors to <u>calculate the concentration of quinine in the original sample</u>:
- 160 ppm * 100mL/15mL = 1066.67 ppm
ppm can be defined as <u>mg of quinine</u>/L solvent:
500 mL solution ⇒ 500/1000 = 0.5 L
- 1066.67 ppm * 0.5L = 533.33 mg quinine
Answer:
The rate law for second order unimolecular irreversible reaction is
![\frac{1}{[A]} = k.t + \frac{1}{[A]_{0} }](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B%5BA%5D%7D%20%3D%20k.t%20%2B%20%5Cfrac%7B1%7D%7B%5BA%5D_%7B0%7D%20%7D)
Explanation:
A second order unimolecular irreversible reaction is
2A → B
Thus the rate of the reaction is
![v = -\frac{1}{2}.\frac{d[A]}{dt} = k.[A]^{2}](https://tex.z-dn.net/?f=v%20%3D%20-%5Cfrac%7B1%7D%7B2%7D.%5Cfrac%7Bd%5BA%5D%7D%7Bdt%7D%20%3D%20k.%5BA%5D%5E%7B2%7D)
rearranging the ecuation
![-\frac{1}{2}.\frac{k}{dt} = \frac{[A]^{2}}{d[A]}](https://tex.z-dn.net/?f=-%5Cfrac%7B1%7D%7B2%7D.%5Cfrac%7Bk%7D%7Bdt%7D%20%3D%20%5Cfrac%7B%5BA%5D%5E%7B2%7D%7D%7Bd%5BA%5D%7D)
Integrating between times 0 to <em>t </em>and between the concentrations of ![[A]_{0}](https://tex.z-dn.net/?f=%5BA%5D_%7B0%7D)
to <em>[A].</em>
![\int\limits^0_t -\frac{1}{2}.\frac{k}{dt} =\int\limits^A_{0} _A\frac{[A]^{2}}{d[A]}](https://tex.z-dn.net/?f=%5Cint%5Climits%5E0_t%20-%5Cfrac%7B1%7D%7B2%7D.%5Cfrac%7Bk%7D%7Bdt%7D%20%3D%5Cint%5Climits%5EA_%7B0%7D%20_A%5Cfrac%7B%5BA%5D%5E%7B2%7D%7D%7Bd%5BA%5D%7D)
Solving the integral
