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Stels [109]
3 years ago
9

Why do scientists follow a set oder of steps when carrying out a scientific investigation?

Chemistry
1 answer:
vazorg [7]3 years ago
5 0

Answer:

If an orderly set of steps is followed, the observations and results are more reliable. The experiment can be conducted again using the sample procedure.

Explanation:

Hope it helps :)

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How many digits to the right of the decimal point should be used to report the result?
aalyn [17]

Answer:

In engineering and science the common stand is two places.

For example if you get a calculation of 4.567 round up and give the result of 4.57

4 0
3 years ago
PLEASE HELP!<br><br> Count the total number of atoms in H 2 O:<br><br> 2<br> 3<br> 4<br> 5<br> 6
Darya [45]
3
two hydrogen and 1 oxygen
8 0
3 years ago
Read 2 more answers
Solid NaI is slowly added to a solution that is 0.0079 M Cu+ and 0.0087 M Ag+.Which compound will begin to precipitate first?NaI
NeTakaya

Answer :

AgI should precipitate first.

The concentration of Ag^+ when CuI just begins to precipitate is, 6.64\times 10^{-7}M

Percent of Ag^+ remains is, 0.0076 %

Explanation :

K_{sp} for CuI is 1\times 10^{-12}

K_{sp} for AgI is 8.3\times 10^{-17}

As we know that these two salts would both dissociate in the same way. So, we can say that as the Ksp value of AgI has a smaller than CuI then AgI should precipitate first.

Now we have to calculate the concentration of iodide ion.

The solubility equilibrium reaction will be:

CuI\rightleftharpoons Cu^++I^-

The expression for solubility constant for this reaction will be,

K_{sp}=[Cu^+][I^-]

1\times 10^{-12}=0.0079\times [I^-]

[I^-]=1.25\times 10^{-10}M

Now we have to calculate the concentration of silver ion.

The solubility equilibrium reaction will be:

AgI\rightleftharpoons Ag^++I^-

The expression for solubility constant for this reaction will be,

K_{sp}=[Ag^+][I^-]

8.3\times 10^{-17}=[Ag^+]\times 1.25\times 10^{-10}M

[Ag^+]=6.64\times 10^{-7}M

Now we have to calculate the percent of Ag^+ remains in solution at this point.

Percent of Ag^+ remains = \frac{6.64\times 10^{-7}}{0.0087}\times 100

Percent of Ag^+ remains = 0.0076 %

8 0
4 years ago
Hwlp meeeeeeeeeeeeeeeeeeee
Vanyuwa [196]
The most appropriate answer is C !!
4 0
3 years ago
Answer question 13. What is the mechanical advantage of a lever that can lift a 100 N load with a input force of 20 N
vazorg [7]
MA= output force/ input force
MA= 100N/20N
MA= 50
8 0
3 years ago
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