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kirza4 [7]
3 years ago
6

Es

Chemistry
1 answer:
babunello [35]3 years ago
8 0

The correct answer is Chemical energy changes to mechanical energy. Chemical energy in the battery powers the mechanical fan. ON USA TEST PREP!!!!!

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How many moles of gas are there in a 50. 0 l container at 22. 0 °c and 825 torr?
andre [41]

2.2311 moles of gas are there in a 50. 0 l container at 22. 0 °c and 825 torrs.

<h3>What is an ideal gas?</h3>

An Ideal gas is a hypothetical gas whose molecules occupy negligible space and have no interactions, and which consequently obeys the gas laws exactly.

Assuming the gas is ideal, we can solve this problem by using the following equation:

PV = nRT

Where:

P = 825 torr ⇒ 825 / 760 = 1.08 atm

V = 50 L

n = ?

R = 0.082 atm·L·mol⁻¹·K⁻¹

T = 22 °C ⇒ 22 + 273.16 = 295.16 K

We input the data:

1.08 atm x 50 L = n x 0.082 atm·L·mol⁻¹·K⁻¹ x 295.16 K

And solve for n:

24.20312

n = 2.2311 mol

Hence, 2.2311 moles of gas are there in a 50. 0 L container at 22. 0 °c and 825 torrs.

Learn more about ideal gas here:

brainly.com/question/23580857

#SPJ4

5 0
3 years ago
If the ka of a monoprotic weak acid is 1.2 × 10-6, what is the ph of a 0.40 m solution of this acid?
frez [133]
First, we write out a balanced equation.
HA <--> H(+) + A(-)

Next, we create an ICE table

        HA     <-->      H+     +    A-
[]i     0.40M            0M           0M
Δ[]    -x                   +x            +x
[]f     0.40-x             x              x

Next, we write out the Ka expression.

Ka = [H+][A-]/[HA]

Ka = x*x/(0.40-x) 

However, because Ka is less than 10^-3, we can assume the amount of dissociation is negligible. Thus,

Assume 0.40-x ≈ 0.40

Therefore, 1.2x10^-6 = x^2/0.40

Then we solve for the [H+] concentration, or x

\sqrt{0.40(1.2*10^{-6})} =x

x=6.93x10^-4

Next, to find pH we do 

pH = -log[H+]

pH = -log[6.93x10^-4]

pH = 3.2
5 0
3 years ago
6. You have $50.00. You buy a CD for $15.50. You sell it to your friend for $12.00. He doesn't
kompoz [17]

Answer: the answer is that you made $2

Explanation:

4 0
3 years ago
The radioactive isotope I-131 is used in
Fudgin [204]
The answer is D, medical diagnosis
3 0
3 years ago
PLEASE I NEED THIS ANSWERED IN 5 MINS
yKpoI14uk [10]
The answer would be: C.  160.3 J/mol*K 

To solve this question, you need to know the equation for Gibbs free energy formula. Entropy is expressed as delta S. The temperature would be expressed as T. Don't forget that temperature use Kelvin as unit, not Celsius

The formula would be:
G= H- T*S
130.5 kJ/mol= 178.3kJ/mol - (25+273.15K)*S
(298.15K)*S=178.3kJ/mol - 130.5 kJ/mol
S= (47.8kJ/mol)/ 298.15K=
S= 0.1603 kJ/mol*K= 160.3 J/mol*K        ------> 1kJ= 1000J
4 0
3 years ago
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