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faltersainse [42]
2 years ago
7

HELP, THANKS

Chemistry
1 answer:
Natasha_Volkova [10]2 years ago
6 0

The mass of the cube with length of 2cm is 320g

  • We were given length of cube as 2cm

<em>To know the volume of cube we can use the expression</em>

<em />

Volume of cube = a^{3}

Where a= length of cube=2cm

Then volume of the cube 2^{3}   = 8 cm.

  • Density was given as (  \frac{40g}{  cm^{3} } )

But we know that density is the ratio of mass to the volume of a substance.

  • ThenDensity=   \frac{ mass     }{  volume    }

But we are looking for mass of the object, the we can make Mass as subject of the formula

  • Mass= density * volume

Them substitute the values

  • Mass = (40 * 8)

= 320g

<em>Therefore mass of the cube is</em> 320g

Learn more at: brainly.com/question/18320053?referrer=searchResults

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Which of the following contains BOTH ionic and covalent bonds? Which of the following contains BOTH ionic and covalent bonds? Ca
Marta_Voda [28]

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CaI₂ has the Ca-I bond where electronegativity of Ca and I are 1 and 2.66. Difference of electronegativity is 1.66 → <em>Bond is covalent.</em>

COS has the C-O and C-S bonds  where electronegativity of C, O and S are 2.55, 3.44 and 2.55. Difference of electronegativity are 0.89 and 0 → <em>Bonds are covalent.</em>

BaSO₄ has the Ba-O and O-S bonds  where electronegativity of Ba, O and S are 0.89, 3.44 and 2.55. Difference of electronegativity are 2.55 and 0.89 → <em>Bonds are ionic and covalent respectively</em><em>.</em>

SF₆ has the S-F bond where electronegativity of S and F are 2.55 and 3.98. Difference of electronegativity is 1.43 → <em>Bond is covalent.</em>

4 0
3 years ago
when 6g acetic acid is dissolved in 1000cm3 of solution then how many molecules ionize out of 1000 acetic acid molecules
iVinArrow [24]

Answer:

24.8 molecules are ionized from 1000 acetic acid molecules.

Explanation:

Acetic acid, CH₃COOH dissociates in water, thus:

CH₃COOH ⇄ CH₃COO⁻ + H⁺

Ka = 6.3x10⁻⁵ = [CH₃COO⁻] [H⁺] / [CH₃COOH]

<em>That means amount of CH₃COO⁻ (the dissociated form) that are produced is followed by the equilibrium of the weak acid.</em>

<em />

The initial molar concentration of acetic acid (Molar mass: 60g/mol) is:

6g ₓ (1mol / 60g) = 0.1 moles acetic acid, in 1000cm³ = 1L.

0.1 moles / L = <em>0.1M</em>

The 0.1M of acetic acid will dissociate producing X of CH₃COO⁻ and H⁺, thus:

[CH₃COOH] = 0.1M - X

[CH₃COO⁻] = X

[H⁺] = X

Replacing in Ka formula:

6.3x10⁻⁵ = [CH₃COO⁻] [H⁺] / [CH₃COOH]

6.3x10⁻⁵ = [X] [X] / [0.1 - X]

6.3x10⁻⁶ - 6.3x10⁻⁵X = X²

6.3x10⁻⁶ - 6.3x10⁻⁵X - X² = 0

Solving for X

X = - 0.0025 → False solution, there is no negative concentrations.

X = 0.00248M

That means, a 0.1M of acetic acid produce:

[CH₃COO⁻] = X = 0.00248M solution of the ionized form.

In a basis of 1000 molecules:

1000 molecules × (0.00248M / 0.1M) = 24.8

<h3>24.8 molecules are ionized from 1000 acetic acid molecules.</h3>
8 0
2 years ago
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