Complete Question
A person throws a pumpkin at a horizontal speed of 4.0 m/s off a cliff. The pumpkin travels 9.5m horizontally before it hits the ground. We can ignore air resistance.What is the pumpkin's vertical displacement during the throw? What is the pumpkin's vertical velocity when it hits the ground?
Answer:
The pumpkin's vertical displacement is 
The pumpkin's vertical velocity when it hits the ground is 
Explanation:
From the question we are told that
The horizontal speed is 
The horizontal distance traveled is 
The horizontal distance traveled is mathematically represented as
Where t is the time taken
substituting values
=> 
Now the vertical displacement is mathematically represented as
now the vertical velocity before the throw is zero
So
Now the final vertical velocity is mathematically represented as
substituting values
Considering that we are talking about a stepdown transformer, and a turn ration of 1:24
Then
Vsecondary coil = 120 V / 24 = 5V
(But lets remember that the power must be conserved in the transformer, so the voltage is 24 times less, but the current is 24 times higher)
It provides 5 volts to operate the player or charge the batteries
Answer:
C and F
Explanation:
A break in one wire causes all current to stop.
If one bulb goes out, the others go out.
Answer:
3.7 m/s^2
Explanation:
The period of a simple pendulum is given by:
where L is the length of the pendulum and g is the free-fall acceleration on the planet.
Calling L the length of the pendulum, we know that:
is the period of the pendulum on Earth, and 
is the free-fall acceleration on Earth
is the period of the pendulum on Mars, and 
is the free-fall acceleration on Mars
Dividing the two expressions we get
And re-arranging it we can find the value of the free-fall acceleration on Mars:
1/2*2.8*x^{2}=2.8*9.81*1.50
X=5.425
Because K.E=1/2*M*V² and it is equal to P.E in the conservation of energy which means its K.E=P.E
P.E=m*g*h
So K.E equals 1/2*2.8*(5.425)²=41.20
