To solve this problem, we use the formula:
I100 / I1 = [P / 4π(100m)^2] / [P / 4π(1m)^2]
I100 / I1 = 1 / 100^2
I100 / I1 = 10^-4
Therefore the change in intensity from 1m to 100m in decibels is:
B100 – B1 = 10 log(10^-4) dB = -40 dB
So the intensity at 100m is calculated as:
B100 = B1 – 40 dB = 140 dB – 40 dB = 100 dB
Answer:
100 dB
Answer:
2.24 T
Explanation:
From Electromagnetic Field,
F = BILsin∅................ Equation 1
Where F = Force on the wire, B = Field strength, I = current flowing in the conductor, L = length of the conductor, ∅ = The angle the conductor makes with the magnetic field.
Making B the subject of the equation,
B = F/ILsin∅..................... Equation 2
Given: F = 2.15 N, I = 32 A, L = 3.00 cm = 0.03 m, ∅ = 90° ( the wire is perpendicular to the magnetic field)
Substitute into equation 2
B = 2.15/(32×0.03×sin90°)
B = 2.15/0.96
B = 2.24 T.
Hence the Field strength = 2.24 T
Answer:
D ko alam pasensya ka na ha
Do not see the statements
