If 250 g of calcium chlorate decomposes into calcium chloride and oxygen, what mass of oxygen would be produced?
1 answer:
115.94g of O₂ are produced by 250g of Ca(ClO₃)₂
<u>Explanation:</u>
Ca(ClO₃)₂ -->CaCl₂ + 3O₂
One mole of calcium chlorate give three moles of oxygen.
Molar mass of calcium chlorate is
40+(35.5+16*3)*2 = 207g/mol
Molar mass of Oxygen = 32g
1 mole of calcium chlorate decomposes to form 3 moles of oxygen.
So,
207g of Ca(ClO₃)₂ produces 3 X 32g of O₂
250g of Ca(ClO₃)₂ will produce =
= 115.94g of O₂
Therefore, 115.94g of O₂ are produced by 250g of Ca(ClO₃)₂
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The value of the force, F₀, at equilibrium is equal to the horizontal
component of the tension in string 2.
Response:
- The value of F₀ so that string 1 remains vertical is approximately <u>0.377·M·g</u>
Given:
The weight of the rod = The sum of the vertical forces in the strings
Therefore;
M·g = T₂·cos(37°) + T₁
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Taking moment about point (2) gives;
M·g × L = T₁ × 2·L
Therefore;
Which gives;
F₀ = T₂·sin(37°)
Which gives;
- F₀ ≈ <u>0.377·M·g</u>
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