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3 years ago

Which statements accurately describe elements?

Physics

2 answers:

alexandr402 [8]3 years ago

8 0

Elements are made up of two or more types of atoms.

Elements are made up of only one type of atom.

Each element has a unique chemical symbol.

Þ Elements can be identified by their àtomid number. I

One element cannot be combined with another elemen

Explanation:

Marysya12 [62]3 years ago

6 0

The statements that describes accurately about elements are :

Elements are made up of only one type of atom.

Each element has a unique chemical symbol.

Elements can be identified by their àtomic number

<u>Explanation:</u>

Simple and complete chemical substances are called elements. An element contains only one type of atom. In a periodic table each of the the element occupies unique entry respectively. The atom that is present in an element contains similar number of protons and this is said to be an atomic number. Each element is represented by an unique one or two letters in the periodic table.

One Element differs for another element by the number of protons present in the nucleus. If there is one proton in an atom it is said to be hydrogen atom and if it has two atoms then it is known to be a helium atom.Lithium refers to the atom with three protons.

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A) Speed in the lower section: 0.638 m/s

B) Speed in the higher section: 2.55 m/s

C) Volume flow rate: $1.8\cdot 10^{-3} m^3/s$

Explanation:

To solve the problem, we can use Bernoulli's equation, which states that

$p_1 + \rho g h_1 + \frac{1}{2}\rho v_1^2 = p_2 + \rho g h_2 + \frac{1}{2}\rho v_2^2$

where

$p_1=1.75\cdot 10^4 Pa$ is the pressure in the lower section of the tube

$h_1 = 0$ is the heigth of the lower section

$\rho=1000 kg/m^3$ is the density of water

$g=9.8 m/s^2$ is the acceleration of gravity

$v_1$ is the speed of the water in the lower pipe

$p_2$ is the pressure in the higher section

$h_2 = 0.250 m$ is the height in the higher pipe

$v_2$ is hte speed in the higher section

We can re-write the equation as

$v_1^2-v_2^2=\frac{2(p_2-p_1)+\rho g h_2}{\rho}$ (1)

Also we can use the continuity equation, which state that the volume flow rate is constant:

$A_1 v_1 = A_2 v_2$

where

$A_1 = \pi r_1^2$ is the cross-section of the lower pipe, with

$r_1 = 3.00 cm =0.03 m$ is the radius of the lower pipe (half the diameter)

$A_2 = \pi r_2^2$ is the cross-section of the higher pipe, with

$r_2 = 1.50 cm = 0.015 m$ (radius of the higher pipe)

So we get

$r_1^2 v_1 = r_2^2 v_2$

And so

$v_2 = \frac{r_1^2}{r_2^2}v_1$ (2)

Substituting into (1), we find the speed in the lower section:

$v_1^2-(\frac{r_1^2}{r_2^2})^2v_1^2=\frac{2(p_2-p_1)+\rho g h_2}{\rho}\\v_1=\sqrt{\frac{2(p_2-p_1+\rho g h_2)}{\rho(1-\frac{r_1^4}{r_2^4})}}=0.638 m/s$