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3 years ago

The difference of the present ages of two sister in 5 yrs

Mathematics

1 answer:

Gekata [30.6K]3 years ago

4 0

Answer:

4 and 9

Step-by-step explanation:

let their ages be x and x - 5, then in 4 years their ages will be

x + 4 and x - 5 + 4 = x - 1 , and the product is 104, thus

(x + 4)(x - 1) = 104 ← expand factors on left using FOIL

x² + 3x - 4 = 104 ( subtract 104 from both sides )

x² + 3x - 108 = 0 ← in standard form

(x + 12)(x - 9) = 0 ← in factored form

Equate each factor to zero and solve for x

x + 12 = 0 ⇒ x = - 12

x - 9 = 0 ⇒ x = 9

However, x > 0 ⇒ x = 9

Thus

Their present ages are 9 and 9 - 5 = 4

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Answer:

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Step-by-step explanation:

Given the 4 inequalities:

s ≥ 12 - 0.5t (1)

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Let substitute this point into (1) we have: 20 ≥ 12 -0.5*0 True

Let substitute this point into (2) we have: 20 ≥ 10 - 0 True

Let substitute this point into (3) we have: 20 ≤ 20 - 0 True

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Let substitute this point into (3) we have: 16 ≤ 20 - 4 True

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