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bogdanovich [222]
3 years ago
14

Jane invested £4000 for 3 years with an interest rate of 1.5%. What was her investment worth at the end of this period?

Mathematics
2 answers:
Gwar [14]3 years ago
8 0

Answer:

$4184

Step-by-step explanation:

a =  p{(1 +  \frac{r}{100} )}^{n}

a = amount

p = principal

r = rate interest

n = number of years

a = 4000[1+(1.5/100)]³

= 4000(1.046)

= $4184

(Correct me if i am wrong)

ddd [48]3 years ago
6 0

Answer:

$4182.7

Step-by-step explanation:= 4000*(1.5%)*3

Year 1= 4000*(100%+1.5%)= 4060

Year 2= 4060*(100%+1.5%)= 4120.9

Year 3= 4120.9*(100%+1.5%)= 4182.7

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Can someone please do this i suck at math
Wittaler [7]

Answer:

Width = y + 7x

Step-by-step explanation:

Area of the rectangle = {y}^{2}  + 8xy + 7 {x}^{2}

Length of the rectangle = y + x

Lets factorise {y}^{2}  + 8xy + 7 {x}^{2}

=  >  {y}^{2}  + xy + 7xy +  {x}^{2}

=  > y(y + x) + 7x(y + x)

=  > (y + 7x)(y + x)

Now ,

Width = \frac{Area}{Length}  =  \frac{(y + 7x)(y + x)}{(y + x)}  = y + 7x

3 0
3 years ago
Zane performs the elementary row operation represented by R2-½R1 on matrix A.​
UkoKoshka [18]

Answer:

[2 5 0]

[-7 -11/2 12]

Step-by-step explanation:

We want to perform elementary row operation represented by R2 - ½R1 on matrix A in the figure attached.

Now, matrix A is given as;

[2 5 0]

[-6 -3 12]

Now, R1 is row 1 = [2 5 0]

R2 is row 2 = [-6 -3 12]

Thus, R2 - ½R1 = [-6 -3 12] - ½[2 5 0]

This gives;

[-6 -3 12] - [1 5/2 0] = [-7 -11/2 12]

Now,[-7 -11/2 12] will be the new row 2 since it's just an elementary row operation we did on the Matrix A.

Thus, the new matrix is now;

[2 5 0]

[-7 -11/2 12]

5 0
3 years ago
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I need help , if yk the answer help fr!!!
Feliz [49]

Answer:

The measure of the angle JKG is:

m∠JKG = 56°

Step-by-step explanation:

<u>Given</u>

m∠JKG = 76-2x

m∠FHK = 6x-4

J is a midpoint of the segment FG and K is a midpoint of the segment GH.

<u>To determine</u>

m∠JKG = ?

Given that J is a midpoint of the segment FG and K is a midpoint of the segment GH. Thus, making two similar triangles, ΔJGK and ΔFGH

We know that two triangles are similar if the only difference is size. So, the angles remain the same.

so m∠JKG and m∠FHK are equal.

i.e.

m∠JKG = m∠FHK

substitute m∠JKG = 76-2x and m∠FHK = 6x-4

76-2x = 6x-4

6x+2x = 76 + 4

8x = 80

divide both sides by 8

8x/8 = 80/8

x = 10

Therefore, the value of x = 10

As

m∠JKG = 76-2x

substitute x = 10

m∠JKG = 76 - 2(10)

             = 76 - 20

             = 56°

Therefore, measure of the angle JKG is:

m∠JKG = 56°

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3 years ago
What is 485 times 34
Svet_ta [14]
The answer is sixteen thousand four hundred ninety
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H(x)=x-4 what’s is the domain of h?
Kazeer [188]

Answer:

all real number

Step-by-step explanation:

since h(x) is polynomial function

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