If AD = 20 centimeters, DC = 15 centimeters,
1 answer:
Answer:
Incomplete question, check attachment for diagram of the question
Step-by-step explanation:
Given that,
AD = 20cm
DC = 15cm
BC = 7cm
AB = 24cm
Since the shape consist of two right angle triangle,
Then, we will find the area of each triangle and add them together to find the area of the quadrilateral ABCD
Area of a triangle can be calculated using
A = ½b×h
Then,
For triangle 1, its area is
A_1 = ½ × DC × AD
A_1 = ½ × 15 × 20
A_1 = 150 cm²
Fro triangle 2
A_2 = ½ × BC × AB
A_2 = ½ × 7 × 24
A_2 = 84 cm²
Then, the total area is
A = A_1 + A_2
A = 150 + 84
A = 234 cm²
Area of the quadrilateral ABCD is 234cm²
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Answer:
(A) 180
Step-by-step explanation:
We have to treat those player selections as independent events, since one doesn't influence the other (the fact you chose Joe as a guard, shouldn't have an influence on who'll pick as center, unless there's bad blood between some players... but that's a whole other story).
So, how many ways to pick 2 guards from a selection of 4? The order doesn't seem to matter here, since they don't specify for example that Joe can only play on the left side). So, it's a pure combination calculation:
C(4,2) = 6.
How many ways to pick the 2 forwards from a group of 5? Using the same calculation, we get:
C(5,2) = 10.
And of course, the coach has 3 ways to pick a center player from 3.
Then we multiply the possible ways to pick guards, forwards and center...
6 * 10 * 3 = 180 ways.