20waves/57.1s = 0.350 Hz
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Partial. a penumbral lunar eclipse is when the moon passes through the earths penumbra
The correct answer is A. True.
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Answer:
0.035 N
Explanation:
Parameters given:
Charge q1 = -3.31x10^(-7) C
Charge q2 = -5.7x10^(-7) C.
Distance between them, R = 22 cm = 0.22 m
Electrostatic force between to particles is given as:
F = (k* q1 * q2) / R²
F = (9 * 10^9 * -3.31 * 10^(-7) * -5.7 * 10^(-7)) / 0.22²
F = 0.035 N
Answer: A.) v = 2πr/T
Explanation:
The tangential speed of an orbiting object can be obtained by the product of the radius of the orbit and the angular speed of the object in a circular motion.
This the tangential seed can be represented mathematically as :
Tangential speed (v) = angular speed(ω) × radius(r)
v = r × ω --------(1)
Recall:
ω = 2π/T
Substituting ω = 2π/T in equation (1)
v = r × 2π/T
v = 2πr/T