All categories

1 year ago

What is an enzyme and what is it from

Physics

1 answer:

k0ka [10]1 year ago

4 0

Answer:

Enzymes help break down food that we consume. They are found in the stomach or small intestine.

You might be interested in

Sultan throws a ball horizontally from his window, 12 m above the garden. It reaches the ground after

Kay [80]

Answer:

Explanation:

<h2><em>Hope it help mark as Brainlist</em></h2>

8 0

3 years ago

What is one type of renewable energy source?

erik [133]

Answer:

Solar energy

Explanation:

6 0

3 years ago

Read 2 more answers

An object is moving at a constant velocity of 4 m/s. What is it's initial velocity?

AysviL [449]

Answer:

How does sperm cells get out of the genitals of the male's? What produces the sperms? Why does women have to hope on the genitals?

kjd;oisdnvliusdh;j;ovh;dfkn'grGXC/?jd;.d

sgo]er]'gr'kspdzg'

d/h

'dfhdf

Explanation:

4 0

3 years ago

A friend tells you that a rowboat is propelled forward by the force of its oars against the water. First explain whether the sta

stellarik [79]

It is correct, the action is paddling, where you move the water backwards, and the reaction is the boat moving forwards.

7 0

3 years ago

Rearrange the equation to solve for the permeability of free space (μ0). Remember that the slope is the ratio of magnetic field

IRINA_888 [86]

Complete Question

The complete question is shown on the first uploaded image

Compare the percent error between your value and the accepted value of 1.26 times 10-6 T · m/A. (Use the accepted value given to three significant figures in your calculation.). 100% % error = %

Answer:

The permeability of free space is $\mu_0 = 1.32*10^{-6} \ Tm/A$

The percentage error is % error = 5.25%

Explanation:

From the question we are told that

The slope is $s= 3.9\ G/A$ , and

Generally $1 \ gauss = 10^{-4 } tesla$

So $s = 3.9 *10^ {-4} T /A$

From the relation given in the question

$\mu_0 = \frac{2R}{N} [\frac{B}{I} ]$

Where R is the radius of the coil $=\frac{Diameter \ of \ coil }{2} = 0.017m$

N is the number of loops of the coil = 10

Now from the question we are told that

$s = \frac{B}{I}$

substituting into the equation above

$\mu_0 = \frac{2R }{N} s$

Substituting values

$\mu_0= \frac{2 * 0.017}{10 } * 3.9*10^{-4}$

$= 1.326 *10^ {-6} \ Tm/A$

Generally the % error is mathematically represented as

% $error = \frac{Measured \ value - accepted \ value}{accepted \ value } *100$

Given that the accepted value is $\mu_o_ {acc} = 1.26 *10 ^{-6} \ T \cdot m /A$

Hence substituting values

% $error = \frac{(1.326-1.26)*10^{-6}}{1.26 *10 ^ {-6}} *100$

$= 5.24$

6 0

3 years ago