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Ugo [173]
3 years ago
12

An electromagnetic wave is transporting energy in the negative y direction. At one point and one instant the magnetic field is i

n the positive x direction. The electric field at that point and instant is:
Why is (D) the answer? I thought it's (C)

a. positive y direction
b. negative y direction
c. positive z direction
d. negative z direction
Physics
1 answer:
natali 33 [55]3 years ago
4 0

Answer:. Option c

Explanation: the speed of an electromagnetic wave is simply the vector product of the magnetic field and the electric field.

The direction of the velocity is the direction of the electromagnetic wave.

The wave is already moving towards the negative y axis (-j) and the magnetic field is already pointing towards the positive x axis (i)

From cross product of unit vectors

i × j = k

i × k = - j

With the second identity, we can see that the electric field will be pointing towards the positive of the x axis (k).

Option c is validated

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Answer:

106417026.88435 m

Explanation:

T = Time period of the satellite = 4 days

m = Mass of the Earth =  5.972 × 10²⁴ kg

G = Gravitational constant = 6.67 × 10⁻¹¹ m³/kgs²

Time period is given by

T=2\pi\sqrt{\dfrac{r^3}{GM}}\\\Rightarrow r=\left(\dfrac{T^2GM}{4\pi ^2}\right)^{\dfrac{1}{3}}\\\Rightarrow r=\left(\dfrac{(4\times 24\times 60\times 60)^2\times 6.67\times 10^{-11}\times 5.972\times 10^{24}}{4\pi ^2}\right)^{\dfrac{1}{3}}\\\Rightarrow r=106417026.88435\ m

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3 years ago
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vovikov84 [41]
Women should eat 1,200 men should eat 1,800
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A hot metal washer is placed in a jar of cool water.
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A car’s velocity as a function of time is given by Vx (t) = α.t + β.t 2 , where α= 3m/s and β= 0.1m/s 3 . Calculate the average
s344n2d4d5 [400]

The definition of average acceleration allows to find the result for the average acceleration in the given time interval is:

          a_{average}= 1.5  \ \frac{m}{s^2}

Instantaneous acceleration is defined as the derivative of velocity with respect to time.

           a =   \frac{dv}{dt}

Where a is the acceleration, v the velocity and t the time.

They indicate that the speed of the car is given by the relation.

          v = α t + β t²

With α = 3 m / s and β = 0.1 m / s³

Let's make  the derivative.

           a = α + 2β t

Let's substitute

            a = 3 + 2 0.1 t

Average acceleration is the change in velocity in the time interval.  

          a_{average} = \frac{\Delta v}{\Delta t }

Let's find the velocity at the indicated time.

For t = 5 s

         v₅ = 3 + 0.1 5²

         v₅ = 5.5 m / s

For t = 10 s

          v₁₀ = 3 + 0.1 10²

          v₁₀ = 13 m / s

Let's calculate the average acceleration.

           a_{average} = \frac{13 - 5.5 }{ 10 - 5 }\\

           a_{average}= 1.5 \  m/s^2

In conclusion using the definition of mean acceleration we can find the result for the mean acceleration in the given time interval is:

           a_{average} =  1.5 m / s²

Learn more here: brainly.com/question/20057878

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