Answer:
(a) 17450.8 J (B) 1.239 sec
Explanation:
We have given power output =8 KW
Heat expelled = 10994 j
Efficiency =37% = 0.37
(A) We know that efficiency 

Heat input =17450.8 J
(B) Work done by the engine is = 17450.8-10994=6456.8 j
Power output is given by 8 KW =8000 W
So time for each cycle is 
The question is incomplete, these are the missing parts of the question.
b) What is the baseball's acceleration in g's? (Indicate the direction with the sign of your answer.)
(b) What is the size of the force acting on it?
Answer:
a) -14333.3ms-2
b) -1462.58g
c) 2078N
Explanation:
The acceleration (deceleration) is easily found from from the information provided. Then the acceleration is obtained in terms of g as shown in the solution attached. The force is obtained from F=ma as shown in the image attached. Note the acceleration is negative because the ball was coming to rest. (The ball was caught).
The weight of an object is mass*acceleration. In this case mass*g.
1000*9.8=9800
So the car has a weight of 9800 N.
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Answer:
(a) 
(b) 
Explanation:
<u>Electric Circuits</u>
Suppose we have a resistive-only electric circuit. The relation between the current I and the voltage V in a resistance R is given by the Ohm's law:

(a) The electromagnetic force of the battery is
and its internal resistance is
. Knowing the equivalent resistance of the headlights is
, we can compute the current of the circuit by using the Kirchhoffs Voltage Law or KVL:

Solving for i

i=2.28\ A
The potential difference across the headlight bulbs is


(b) If the starter motor is operated, taking an additional 35 Amp from the battery, then the total load current is 2.28 A + 35 A = 37.28 A. Thus the output voltage of the battery, that is the voltage that the bulbs have is
