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Veronika [31]
3 years ago
7

How do scientist determine how old the world is and the fossils inside of it?

Physics
4 answers:
algol [13]3 years ago
8 0
Yeah they usually see how far down in the ground a fossil is and if it’s deep down they know it’s very old if it’s not deep down then it ain’t very old
valkas [14]3 years ago
6 0

The layers of the fossil the oldest is usual the bottom layer,and the top layer is the newest layer

yaroslaw [1]3 years ago
5 0
Yeah they usually see how far down in the ground a fossil is and if it’s deep down they know it’s very old if it’s not deep down then it ain’t very old
Mazyrski [523]3 years ago
5 0
Yeah they usually see how far down in the ground a fossil is and if it’s deep down they know it’s very old if it’s not deep down then it ain’t very old
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The first one is Force & the second one Power.
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3 years ago
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What type a medium is a ocean wave
andre [41]
Ocean waves travel through the medium called
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A small but measurable current of 3.8 × 10-10 A exists in a copper wire whose diameter is 2.5 mm. The number of charge carriers
Karolina [17]

Answer:

a) 4.9*10^-6

b) 5.71*10^-15

Explanation:

Given

current, I = 3.8*10^-10A

Diameter, D = 2.5mm

n = 8.49*10^28

The equation for current density and speed drift is

J = I/A = (ne) Vd

A = πD²/4

A = π*0.0025²/4

A = π*6.25*10^-6/4

A = 4.9*10^-6

Now,

J = I/A

J = 3.8*10^-10/4.9*10^-6

J = 7.76*10^-5

Electron drift speed is

J = (ne) Vd

Vd = J/(ne)

Vd = 7.76*10^-5/(8.49*10^28)*(1.60*10^-19)

Vd = 7.76*10^-5/1.3584*10^10

Vd = 5.71*10^-15

Therefore, the current density and speed drift are 4.9*10^-6

And 5.71*10^-15 respectively

3 0
2 years ago
A 4.44 l container holds 15.4 g of oxygen at 22.55°c. what is the pressure?
padilas [110]
We will use the ideal gas equation:
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5 0
3 years ago
The displacement of a car is a function of time as follows: x(t)=25+3.0t², with x is in meters. Find the average velocity betwee
aniked [119]

Answer: 15m/s

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v=\frac{\Delta x}{\Delta t}

At t₁ = 1.0s, displacement x₁ is:

x(1)=25+3(1)^{2}

x(1) = 28

At t₂ = 4.0s:

x(4)=25+3(4)^{2}

x(4) = 73

Then, average speed is

v=\frac{73-28}{4-1}

v = 15

The average velocity of a car between t₁ = 1s and t₂ = 4s is 15m/s

5 0
2 years ago
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