Answer: The magnitude of impulse imparted to the ball by the golf club is 2.2 N seconds
Explanation:
Force applied on the golf ball = ![5.0\times 10^3 N](https://tex.z-dn.net/?f=5.0%5Ctimes%2010%5E3%20N)
Mass of the ball = 0.05 kg
Velocity with which ball is accelerating = 44 m/s
Time period over which forece applied = t
![f=ma=\frac{m\times v}{t}](https://tex.z-dn.net/?f=f%3Dma%3D%5Cfrac%7Bm%5Ctimes%20v%7D%7Bt%7D)
![t=\frac{0.05 kg\times 44m/s}{5.0\times 10^3 N}=4.4\times 10^{-4} seconds](https://tex.z-dn.net/?f=t%3D%5Cfrac%7B0.05%20kg%5Ctimes%2044m%2Fs%7D%7B5.0%5Ctimes%2010%5E3%20N%7D%3D4.4%5Ctimes%2010%5E%7B-4%7D%20seconds)
Newton seconds
The magnitude of impulse imparted to the ball by the golf club is 2.2 N seconds
Answer:
A. ![U_0 = \dfrac{\epsilon_0 A V^2}{2d}](https://tex.z-dn.net/?f=U_0%20%3D%20%5Cdfrac%7B%5Cepsilon_0%20A%20V%5E2%7D%7B2d%7D)
B. ![U_1 = \dfrac{\epsilon_0 A V^2}{6d}](https://tex.z-dn.net/?f=U_1%20%3D%20%5Cdfrac%7B%5Cepsilon_0%20A%20V%5E2%7D%7B6d%7D)
C. ![U_2 = \dfrac{K\epsilon_0 A V^2}{2d}](https://tex.z-dn.net/?f=U_2%20%3D%20%5Cdfrac%7BK%5Cepsilon_0%20A%20V%5E2%7D%7B2d%7D)
Explanation:
The capacitance of a capacitor is its ability to store charges. For parallel-plate capacitors, this ability depends the material between the plates, the common plate area and the plate separation. The relationship is
![C=\dfrac{\epsilon A}{d}](https://tex.z-dn.net/?f=C%3D%5Cdfrac%7B%5Cepsilon%20A%7D%7Bd%7D)
is the capacitance,
is the common plate area,
is the plate separation and
is the permittivity of the material between the plates.
For air or free space,
is
called the permittivity of free space. In general,
where
is the relative permittivity or dielectric constant of the material between the plates. It is a factor that determines the strength of the material compared to air. In fact, for air or vacuum,
.
The energy stored in a capacitor is the average of the product of its charge and voltage.
![U = \dfrac{QV}{2}](https://tex.z-dn.net/?f=U%20%3D%20%5Cdfrac%7BQV%7D%7B2%7D)
Its charge,
, is related to its capacitance by
(this is the electrical definition of capacitance, a ratio of the charge to its voltage; the previous formula is the geometric definition). Substituting this in the formula for
,
![U = \dfrac{CV^2}{2}](https://tex.z-dn.net/?f=U%20%3D%20%5Cdfrac%7BCV%5E2%7D%7B2%7D)
A. Substituting for
in
,
![U_0 = \dfrac{\epsilon_0 A V^2}{2d}](https://tex.z-dn.net/?f=U_0%20%3D%20%5Cdfrac%7B%5Cepsilon_0%20A%20V%5E2%7D%7B2d%7D)
B. When the distance is
,
![U_1 = \dfrac{\epsilon_0 A V^2}{2\times3d}](https://tex.z-dn.net/?f=U_1%20%3D%20%5Cdfrac%7B%5Cepsilon_0%20A%20V%5E2%7D%7B2%5Ctimes3d%7D)
![U_1 = \dfrac{\epsilon_0 A V^2}{6d}](https://tex.z-dn.net/?f=U_1%20%3D%20%5Cdfrac%7B%5Cepsilon_0%20A%20V%5E2%7D%7B6d%7D)
C. When the distance is restored but with a dielectric material of dielectric constant,
, inserted, we have
![U_2 = \dfrac{K\epsilon_0 A V^2}{2d}](https://tex.z-dn.net/?f=U_2%20%3D%20%5Cdfrac%7BK%5Cepsilon_0%20A%20V%5E2%7D%7B2d%7D)
Answer: angular displacement in rad = 3038.45 rad
angular displacement in rev = 483.589 rev
Explanation: mathematically
Angular velocity = angular displacement / time taken.
Angular velocity = 33.5 rad/s, time taken = 90.7s
33.5 = angular displacement /90.7
Angular displacement = 33.5 * 90.7 = 3038.45 rad
But 1 rev =2π
Hence 3038.45 rad to rev is
3038.45/2π = 483.599 rev
Answer:
Explanation:
height of Ellipse
i.e.
Width of Ellipse ![=22 cm](https://tex.z-dn.net/?f=%3D22%20cm)
i.e.
Equation of a vertical Ellipse is
at
Answer: 1.176×10^-3 s
Explanation: The time constant formulae for an RC circuit is given below as
t =RC
Where t = time constant , R = magnitude of resistance = 21 ohms , C = capacitance of capacitor = 56 uf = 56×10^-6 F
t = 56×10^-6 × 21
t = 1176×10^-6
t = 1.176×10^-3 s