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Minchanka [31]
3 years ago
6

1. An insect inside a bus flies from the back toward the front at 2 m/s. The bus is moving in a

Physics
1 answer:
borishaifa [10]3 years ago
3 0
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What is the coefficient for titanium tetrachloride when the equation below is balanced?
Alexus [3.1K]

the coefficient of TiCl4 would be 1

3 0
3 years ago
A negatively charged particle (charge = -1e) has a velocity of 6.0 × 106 m/s in the positive x direction at a point where the ma
Anni [7]

Answer:

a=2.6x10^{18} m/s^2

Explanation:

v=6.0x10^6 m/s, q=1.6x10^{-19}C, q=9.11x10^{-31}kg

\beta=\beta_x=3.0T, \beta_y=1.5 T, \beta_y=2.0 T

F_b=q*\left[\begin{array}{ccc}i&j&k\\6x10^6&0&0\\3&1.5&2\end{array}\right]

F_b=-1.6x10^{-19}C*[-12x10^6 j + 9x10^6 k]

F_b=m*a

19.2x10^{-13}j-14.4x10^{-13}k=m*a

a=\frac{19.2x10^{-13}}{9.11x10{-31}}-\frac{14.4x10^{-13}}{9.11x10{-31}}

a=2.107 x10^{18}j-1.58x10^{18}k

a=\sqrt{(2.107x10^{18})^2-(1.57x10^{18})^2}

a=2.6x10^{18} m/s^2

7 0
3 years ago
the velocity of a car increases from 2.0 m/s to 16.0 m/s in a time period of 3.5 s. what was the average acceleration? if an aut
Oksana_A [137]

The Average acceleration is 3.25m/s².

Acceleration is the change in velocity of the body with respect to time.

Where,

a= acceleration

u= initial speed

v= final speed

t= time

Initially, u = 2m/s

v = 16m/s

t = 3.5s

a = v-u/t

a = 16-2/3.5

a = 4m/s²

Then, u = 26m/s

v = 18m/s

t = 4s

a = v-u/t

a = 26-18/4

a =2 m/s²

Now, u = 0m/s

v = 20m/s

t = 2s

a = v-u/t

a = 20/2

a = 10m/s²

Finally, u = 20m/s

v = 10m/s

t = 2s

a = v-u/t

a = 10-20/2

a = -5m/s²

The average acceleration is the acceleration during the entire journey = 4+2+10-5/4

Average acceleration = 13/4m/s²

Average acceleration = 3.25m/s²

The Average acceleration is 3.25m/s²

Learn more about Acceleration here, brainly.com/question/2303856

#SPJ4

7 0
2 years ago
What kind of friction exists between solid objects moving in water?
eduard
Fluid Friction exists when it is acted upon an object when in fluid.


6 0
3 years ago
The frequency of the middle c note on a piano is 261.63 hz. What is the wavelength of this note in centimeters? The speed of sou
Sholpan [36]

Answer:

1.31 m

Explanation:

The relationship between frequency and wavelength of a sound wave is

c=f \lambda

where

c is the speed of the wave

f is the frequency

\lambda is the wavelenfth

In this problem, we have

c = 343.06 m/s

f = 261.63 Hz

So we can solve the formula for the wavelength:

\lambda=\frac{c}{f}=\frac{343.06 m/s}{261.63 Hz}=1.31 m

8 0
3 years ago
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