Each and every capacitor carry Q/3 charge .
Discussion:
The potential drop throughout all of the capacitors should be identical when they are linked in parallel since their endpoints are all the same.
On the contrary hand, each capacitor will get a portion of the total charge flowing from the source. Each charge's value will vary depending on its unique value for C.
Provided:
Q = total charge
Let's assume that charges will be present when they flow through capacitors 1, 2, and 3.
q₁, q₂ & correspondingly, q₃.
From node "A," the charge will now be split into three branches, and it may be expressed as:
Q=q₁+q₂+q₃
Since they are all connected in parallel, the voltage would remain constant.
So, V₁ = V₂ = V₃
q₁/C₁ =q₂/C₂ =q₃/C₃
As each capacitor are same,
So, C = C₁ = C₂ = C₃
or, it can be said,
q₁ /C = q₂/C = q₃/C
q₁ = q₂= q₃
hence,
q+q+q =Q
or, q = Q/3
Therefore from the above calculation, it can be said that each capacitor carries 1/3 of the total charge i.e., Q/3.
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