By using the orbital period equation we will find that the orbital radius is r = 4.29*10^11 m
<h3>
What is the orbital period?</h3>
This would be the time that a given body does a complete revolution in its orbit.
It can be written as:

Where:
- π = 3.14
- G is the gravitational constant = 6.67*10^(-11) m^3/(kg*s^2)
- M is the mass of the sun = 1.989*10^30 kg
- r is the radius, which we want to find.
Rewriting the equation for the radius we get:
![T = \sqrt{\frac{4*\pi ^2*r^3}{G*M} }\\\\r = \sqrt[3]{ \frac{T^2*G*M}{4*\pi ^2} }](https://tex.z-dn.net/?f=T%20%3D%20%5Csqrt%7B%5Cfrac%7B4%2A%5Cpi%20%5E2%2Ar%5E3%7D%7BG%2AM%7D%20%7D%5C%5C%5C%5Cr%20%3D%20%5Csqrt%5B3%5D%7B%20%5Cfrac%7BT%5E2%2AG%2AM%7D%7B4%2A%5Cpi%20%5E2%7D%20%7D)
Where T = 7.5 years = 7.5*(3.154*10^7 s) = 2.3655*10^8 s
Replacing the values in the equation we get:
![r = \sqrt[3]{ \frac{(2.3655*10^8 s)^2*(6.67*10^{-11} m^3/(kg*s^2))*(1.989*10^{30} kg)}{4*3.14 ^2} } = 4.29*10^{11 }m](https://tex.z-dn.net/?f=r%20%3D%20%5Csqrt%5B3%5D%7B%20%5Cfrac%7B%282.3655%2A10%5E8%20s%29%5E2%2A%286.67%2A10%5E%7B-11%7D%20m%5E3%2F%28kg%2As%5E2%29%29%2A%281.989%2A10%5E%7B30%7D%20kg%29%7D%7B4%2A3.14%20%5E2%7D%20%7D%20%3D%204.29%2A10%5E%7B11%20%7Dm)
So the orbital radius is 4.29*10^11 m
If you want to learn more about orbits, you can read:
brainly.com/question/11996385
A material must readily accept electron flow to be a good conductor of electricity. Electrical conductors are electrical charge carriers with electrons that move with ease from atom to atom when charged with voltage. Examples of good conductors are copper, brass, steel, gold, and aluminum.
I need Explanation please
I think its A: Translucent hope this helps if I'm wrong I'm sorry