The question given is incomplete, I googled and got the complete question as below:
You are a waterman daily plying the waters of Chesapeake Bay for blue crabs (Callinectes sapidus), the best-tasting crustacean in the world. Crab populations and commercial catch rates are highly variable, but the fishery is under constant pressure from over-fishing, habitat destruction, and pollution. These days, you tend to pull crab pots containing an average of 2.4 crabs per pot. Given that you are economically challenged as most commercial fishermen are, and have an expensive boat to pay off, you’re always interested in projecting your income for the day. At the end of one day, you calculate that you’ll need 7 legal-sized crabs in your last pot in order to break even for the day. Use these data to address the following questions. Show your work.
a. What is the probability that your last pot will have the necessary 7 crabs?
b. What is the probability that your last pot will be empty?
Answer:
a. Probability = 0.0083
b. Probability = 0.0907
Step-by-step explanation:
This is Poisson distribution with parameter λ=2.4
a)
The probability that your last pot will have the necessary 7 crabs is calculated below:
P(X=7)= {e-2.4*2.47/7!} = 0.0083
b)
The probability that your last pot will be empty is calculated as:
P(X=0)= {e-2.4*2.40/0!} = 0.0907
The answer to this problem is simple all you have to do is pemdas and you get the answer 0.6
Answer:
197.92
Step-by-step explanation:
pretty simple not hard bub
Answer:
∠C=90°
∠A=67°
∠B=23°
Step-by-step explanation:
For angle C:
Thales' Theorem states that an angle inscribed across a circle's diameter is always a right angle.
Therefore, since AB is the diameter(hypotenuse) then angle C is the right angle. (90°)
For Angle A:
The measure of arc BC= 134 degrees. We can just use a formula for an inscribed triangle. ∠A = 1/2 (mBC)
∠A= (1/2)134
∠A= 77°
For angle B:
All triangle angles all add up to 180. We can just subtract angles A and C from 180°:
∠B = 180-(90+67)
∠B = 23°
What you do is add up all the values, then divide by the number of values.
The average of the data is
4.8575.
