Answer:
find the bottom angle of the triangle on the right side.
180 - 92 = 88
Now find x
88+36 = 124
180-124 = <u>56 = x</u>
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Hope that answers your question
Don't hesitate to comment if you are confused about something
Step-by-step explanation:
9514 1404 393
Answer:
D. 12
Step-by-step explanation:
There are a number of ways to find the area of this rectangle. Perhaps the most straightforward is to find the lengths of the sides and multiply those. The distance formula is useful.
d = √((x2 -x1)^2 +(y2 -y1)^2)
Using the two upper-left points, we find the length of that side to be ...
d = √((3 -0)^2 +(3 -0)^2) = √(9 +9) = √18 = 3√2
Similarly, the length of the lower-left side is ...
d = √((-2 -0)^2 +(-2 -0)^2) = √(4+4) = √8 = 2√2
Then the area of the rectangle is ...
A = LW
A = (3√2)(2√2) = 3·2·(√2)^2 = 3·2·2 = 12
The area of rectangle ABCD is 12.
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Other methods include subtracting the area of the corner triangles from the area of the bounding square:
5^2 -2(1/2)(3·3) -2(1/2)(2·2) = 25 -9 -4 = 12
X^2 + 8x + 3
= (x + 4)^2 - 16 + 3
= (x + 4)^2 - 13 Answer.
You divide the + 8 by 2 to get the +4 and you then subtract 4^2 ( which is the -16).
The answer is 40% hope this helps! <3
9514 1404 393
Answer:
- see below for a sketch
- 12 km
Step-by-step explanation:
The distance can be calculated using the Law of Cosines. The angle internal to the triangle at Q is (180°-(146° -65°)) = 99°. Then the distance PR can be found from ...
PR² = PQ² +QR² -2·PQ·QR·cos(∠PQR)
PR² = 6² +10² -2·6·10·cos(99°) ≈ 154.77
PR ≈ √154.77 ≈ 12.44 . . . . km
The distance PR is about 12 km.