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poizon [28]
3 years ago
8

Please help me on this work please !

Mathematics
1 answer:
belka [17]3 years ago
5 0
The second one I beileve is the answer to your question
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HELP ME PLEASE ILL GIVE BRAINLIEST
Alex73 [517]

Answer:

la respuesta correcta es la c

step explanation:

la respuesta correcta es la c

7 0
3 years ago
The volume of a cylinder is 252π cm3 and its height is 7 cm. What is the cylinder’s radius? A. 36 B. 80 C.16 D.6
REY [17]
Put the given information into the formula and solve for the variable of interest.
.. V = π*r^2*h
.. 252π = π*r^2*7
.. (252π)/(7π) = r^2
.. 36 = r^2
.. 6 = r

The radius is 6 cm. Selection D is appropriate.

_____
We would prefer that the offered selections had the appropriate cm units attached.
5 0
3 years ago
In a certain year, the population of Smallburg was $4{,}000.$ In the following year, the population increased by $15\%.$ What wa
makkiz [27]

Answer:

4,600

Step-by-step explanation:

To solve this problem, we need to multiply add 15% of 4,000 back to 4,000.

First, change 15% into a decimal:

15% -> \frac{15}{100} -> 0.15

Next, multiply 4,000 by 0.15:

x= 4,000(0.15)

x=600

The last step is to add the 600 back to 4,000:

4,000 + 600 = 4,600

The population of Smallburg the following year was 4,600.

5 0
3 years ago
F(n)=5.(-2)n-1<br>Complete the recursive formula of f(n).​
Alex73 [517]

Answer:

a(n) = (-2)(a_{n-1})

a_{1}=5

Step-by-step explanation:

The given expression is in the form of the explicit formula of a geometric sequence.

f(n) = a(r)^{n-1}

Where 'a' = First term of the sequence

r = common ratio

Recursive formula of a geometric sequence is,

a(n) = (a_{n-1}).(r)^{n-1}

a(n) = (-2)(a_{n-1})

Where, a_{1}=5

So the recursive formula will be a(n) = (-2)(a_{n-1})

6 0
3 years ago
HELP! What is the solution to the following system of equations?
tatuchka [14]

Answer:

it is 2,4

Step-by-step explanation:

The point that they meet is 2,4 . It means X+ is 2 and Y+ is 4 .

You can write a as their meet point . you should answer like this a(2,4) .

4 0
3 years ago
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