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poizon [28]
4 years ago
8

Please help me on this work please !

Mathematics
1 answer:
belka [17]4 years ago
5 0
The second one I beileve is the answer to your question
You might be interested in
A new shopping mall records 120 total shoppers on their first day of business. Each day after that, the number of shoppers is 10
Marta_Voda [28]

Answer:

1138

Step-by-step explanation:

From the information given:

We can represent it perfectly in an exponential form:

m  = p(q)^x

where;

p = initial value = 120

q = base of the exponential form

q = 1 + r

here; r = rate in decimal = 10% = 0.1

Then q can now be = 1 + 0.1 = 1.1

Replacing it into the exponential form, we get:

m = 120(1.1)^x

where;

x = number of days and m = number of shoppers

Thus:

For the first day:

m = 120(1.1)^x

m = 120

For the second day:

m = 120(1.1)^1

m = 132

For the third day:

m = 120(1.1)^2

m = 145.2

For the fourth day

m = 120(1.1)^3

m = 159.72

For the  fifth-day

m = 120(1.1)^4

m = 175.692

For the sixth-day

m = 120(1.1)^5

m = 193.2612

For the seventh-day

m = 120(1.1)^6

m = 212.58732

Thus; the total numbers of shoppers for the first 7 days is:

= 120+ 132 + 145.2 + 159.72 + 175.692+193.2612+212.58732

= 1138.46052

≅ 1138

6 0
3 years ago
If two angles are complementary. One angle measures 22 degrees. And the other angle measures 2x degrees, what is the value of x?
levacccp [35]

Answer:

x=34

Step-by-step explanation:

34*2=68

68+22=90

A complementary angle adds up to 90 degrees.

5 0
3 years ago
There are 7800 grams of lodine that have a half-life of 8 days. How much lodine will remain after 40 days?
anygoal [31]

Given that we know the initial mass of Iodine and its half-life, we want to see how much will remain after 40 days.

After 40 days, 244.17 grams of Iodine will remain.

<h3 /><h3>The half-life of materials and how to use it:</h3>

The half-life of a material is the time it takes for that amount of material to reduce to its half.

We can model the amount of Iodine as:

A(t) = A*e^{k*t}

  • Where A is the initial amount, in this case, 7800g.
  • k is a constant that depends on the half-life.
  • t is the time in days.

Replacing what we know, we get:

A(t) = 7800g*e^{k*t}

Now we use the fact that the half-life is 8 days, this means that:

e^{k*8} = 1/2

ln(e^{k*8}) = ln(1/2)

k*8 = ln(1/2)

k = ln(1/2)/8 = -0.0866

Then the function is:

A(t) =  7800g*e^{-0.0866*t}

So now we just need to evaluate this in t = 40.

A(40) = 7800g*e^{-0.0866*40} = 244.17g

So, after 40 days, 244.17 grams of Iodine will remain.

If you want to learn more about half-life and decays, you can read:

brainly.com/question/11152793

3 0
2 years ago
What percent of 88 is 154?
lesantik [10]

Answer:

It Is 175% Of 88.

Step-by-step explanation:

154 ÷ 88 = 1.75

To Convert A Decimal Into Percent, You Multiply By 100.

1.75 · 100% = 175%

Therefore, The Answer Is 175%.

5 0
4 years ago
Can someone please help me asap
attashe74 [19]

Answer:

y=3x-4

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
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