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Temka [501]
3 years ago
6

A cell phone company orders 600 new phones from a manufacturer. If the probability of a phone being defective is 3.5%, predict h

ow many of the phones are likely to be defective. Round to the nearest whole number.
18 phones
21 phones
210 phones
26 phones
Mathematics
1 answer:
earnstyle [38]3 years ago
5 0
To determine the number of cellphones likely to be defective, multiply the number of phones ordered by the probability. In this item, the product of 600 and 3.5% or 0.035 is 21. Therefore, 21 out of 600 phones are likely to be defective. The answer is the second among the choices. 
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Which of the following is NOT an observation about critical​ values? Choose the correct answer below. A. The number is a critica
Bess [88]

The correct options are;

A. The number z_α/2 is a critical value that corresponds to an area of 1 − α/2 to its left.

B. The number z_α/2 is a critical value that is a z score with the property that

it separates an area of α/2 in the right tail of the standard normal distribution.

C. A critical value is the number on the borderline separating sample statistics that are likely to occur from those that are unlikely to occur.

D. A critical value is the area in the right-tail region of the standard normal curve.

Answer:

Option D: A critical value is the area in the​ right - tail region of the standard normal curve.

Step-by-step explanation:

A critical value is defined as the line on a graph that makes that graph split into sections.

Now, either one or two of the sections split will fall into the “rejection region“.

So, if the test value falls into the rejection region, it means we will reject the null hypothesis.

Looking at the options given, options A, B & C are possible observations that we could deduce about critical values based on the definition given above.

Option D is not an observation because the critical value is what denotes the z-score with an area of alpha in the right tail region

5 0
3 years ago
Solve for x:2x^2-5x-3=0​
skad [1K]

Answer:

The value of x = 3 or -1/2

Step-by-step explanation:

2x²-5x-3=0

=> 2x² - 6x + x - 3 =0

=> 2x ( x - 3) + 1 ( x -3) =0

=> (2x+1) ( x-3) =0

x = 3 or x = -1/2

8 0
2 years ago
A college student is interested in investigating the TV-watching habits of her classmates and surveys 20 people on the number of
Alla [95]

Answer:

80% confidence interval of the true average number of hours of TV watched per week is [8.28 hours, 11.02 hours].

Step-by-step explanation:

We are given that a college student is interested in investigating the TV-watching habits of her classmates and surveys 20 people on the number of hours they watch per week. The results are provided below;

<u>Hours of TV per week (X)</u>: 6, 14, 13, 6, 16, 10, 19, 4, 5, 5, 18, 8, 7, 14, 8, 8, 9, 12, 6, 5.

Firstly, the Pivotal quantity for 80% confidence interval for the true average is given by;

                                P.Q. =  \frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }  ~ t_n_-_1

where, \bar X = sample mean number of hours of TV watched per week = \frac{\sum X}{n} = 9.65

            s = sample standard deviation = \sqrt{\frac{\sum (X -\bar X)^{2} }{n-1} }  = 4.61

            n = sample of people = 20

           \mu = true average number of hours of TV watched per week

<em>Here for constructing 80% confidence interval we have used One-sample t-test statistics as we don't know about population standard deviation.</em>

<u>So, 80% confidence interval for the true average, </u>\mu<u> is ;</u>

P(-1.33 < t_1_9 < 1.33) = 0.80  {As the critical value of t at 19 degrees of

                                               freedom are -1.33 & 1.33 with P = 10%}  

P(-1.33 < \frac{\bar X-\mu}{\frac{s}{\sqrt{n} } } < 1.33) = 0.80

P( -1.33 \times {\frac{s}{\sqrt{n} } } < {\bar X-\mu} < 1.33 \times {\frac{s}{\sqrt{n} } } ) = 0.80

P( \bar X-1.33 \times {\frac{s}{\sqrt{n} } } < \mu < \bar X+1.33 \times {\frac{s}{\sqrt{n} } } ) = 0.80

<u>80% confidence interval for</u> \mu = [ \bar X-1.33 \times {\frac{s}{\sqrt{n} } } , \bar X+1.33 \times {\frac{s}{\sqrt{n} } } ]

                                         = [ 9.65-1.33 \times {\frac{4.61}{\sqrt{20} } } , 9.65+1.33 \times {\frac{4.61}{\sqrt{20} } } ]

                                         = [8.28 hours, 11.02 hours]

Therefore, 80% confidence interval of the true average number of hours of TV watched per week is [8.28 hours, 11.02 hours].

7 0
3 years ago
Translate to word form:
Svetlanka [38]
1. The total of x and 29.

This is because we see addition going on, so x+29 is the total of something


Hope this helps :)
5 0
3 years ago
Sarah and Nathan each picked a bucket of strawberries. Sarah picked 4 1/4 pounds, and Nathan picked 3 3/4 pounds. How many pound
UNO [17]
4 + 3 is 7, 1/4 + 3/4 is one pound. so 4+3+1= 8..................
3 0
4 years ago
Read 2 more answers
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