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Mila [183]
3 years ago
5

In the presence of a base, blue litmus paper will .O turn purplestay blueto turn red​

Chemistry
2 answers:
Inessa05 [86]3 years ago
7 0

Answer:

In the presence of a base, blue litmus paper will turn red........

Strike441 [17]3 years ago
5 0

Answer:

In the presence of a base the blue litmus paper would remain blue.

Explanation:

This is because the litmus paper will react depending on the pH of the solution added. If the solution is acidic pH < 7, the litmus paper will turn red. If the solution is basic, pH > 7  the litmus paper will turn blue. If the litmus paper is blue when a base is added it will remain blue.

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Which sentences describe decomposers in a food chain?
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hey are the final link in the energy flow in a food chain or a food web. They are fungi and animals that feed on dead organic mattet.

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How do we measure the acidity of rain?
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The following balanced equation shows the decomposition of water (H2O). According to the equation, how many oxygen atoms are in
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When heated to 150 ºC, CuSO4.5 H2O loses its water of hydration as gaseous H2O. A 2.50 g sample of the compound is placed in a s
Katyanochek1 [597]

Answer:

Water pressure 0.5 atm

Total Pressure= 2.27  atm

Explanation:

To answer this problem, one has to realize that there are two processes that increase the temperature of the sealed vessel.

First, the dry air in the sealed vessel will be heated which will cause its pressure to increase and it can be determined by the equation:

P₁ x T₂   = P₂ x T₁  ∴  P₂ =  P₁ x T₂ / T₁

For the second process, we have an amount of n moles of water which will be released when the copper sulfate is heated. In this case, to determine the value of the the water gas we will use the gas law:

   PV = nRT  ∴ P =  nRT/V

n will we calculated from the quantity of sample.

2.50 g  CuSo₄ 5H₂O x  1 mol/ 249.69 g = 0.01 mol CuSo₄ 5H₂O

the amount water of hydration is

= 0.01 mol CuSo₄ 5H₂O * 5 mol H₂O / 1 mol CuSo₄ 5H₂O

= 0.05 mo H₂O

pressure of dry air at the final temperature,

P₂ = 1 atm x 500 K/ 300 K = 1.67 atm

Pressure of water :

P (H₂O) 0.05 mol x 0.08206 Latm/kmol x 500 K/ 4 L = 0.5 atm

∴ Total Pressure =  1.67 atm

H2O Pressure = 0.5 atm

5 0
3 years ago
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