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Mila [183]
3 years ago
5

In the presence of a base, blue litmus paper will .O turn purplestay blueto turn red​

Chemistry
2 answers:
Inessa05 [86]3 years ago
7 0

Answer:

In the presence of a base, blue litmus paper will turn red........

Strike441 [17]3 years ago
5 0

Answer:

In the presence of a base the blue litmus paper would remain blue.

Explanation:

This is because the litmus paper will react depending on the pH of the solution added. If the solution is acidic pH < 7, the litmus paper will turn red. If the solution is basic, pH > 7  the litmus paper will turn blue. If the litmus paper is blue when a base is added it will remain blue.

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Studying the decay of radioactive isotopes in dead organisms helps scientists to identify fossilized remains. The ratio of C-12
lidiya [134]

Explanation:

The 3rd one is your answer

5 0
3 years ago
A 8.00g of a certain Compound X, known to be made of carbon, hydrogen and perhaps oxygen, and to have a molecular molar mass of
Ne4ueva [31]

Answer:

C3H6.

Explanation:

Data obtained from the question:

Mass of the compound = 8g

Mass of CO2 = 24.01g

Mass of H2O = 13.10g

Next, we shall determine the mass of C, H and O present in the compound. This is illustrated below:

Molar Mass of CO2 = 12 + (2x16) = 44g/mol

Molar Mass of H2O = (2x1) + 16 = 18g/mol

Mass of C in compound = Mass of C/Molar Mass of CO2 x 24.01

=> 12/44 x 24.01 = 6.5g

Mass of H in the compound = Mass of H/Molar Mass of H2O x 13.1

=> 2x1/18 x 13.1 = 1.5g

Mass of O in the compound = Mass of compound – (mass of C + Mass of H)

=> 8 – (6.5 + 1.5) = 0

Next, we shall determine the empirical formula of the compound. This is illustrated below:

C = 6.5g

H = 1.

Divide by their molar mass

C = 6.5/12 = 0.54

H = 1.4/1 = 1.

Divide by the smallest

C = 0.54/0.54 = 1

H = 1/0.54 = 2

Therefore, the empirical formula is CH2

Finally, we shall determine the molecular formula as follow:

The molecular formula of a compound is a multiple of the empirical formula.

Molecular formula = [CH2]n

[CH2]n = 44

[12 + (2x1)]n = 44

14n = 44

Divide both side by 14

n = 44/14

n = 3

Molecular formula = [CH2]n = [CH2]3 = C3H6

Therefore, the molecular formula of the compound is C3H6

4 0
3 years ago
Do you<br> think a colony on Mars should be nearer the northern or southern<br> polar cap? Explain.
xxTIMURxx [149]

Answer:Hola TvT

Explanation:When the Martian polar caps were first viewed through telescopes, most scientists believed that they were made of water ice, like the polar caps on Earth. Like Earth, Mars has a North and South Pole. But while Earth's polar ice caps consist solely of water ice, Mars' polar caps are a combination of water ice and carbon dioxide ice. As the Martian seasons change, the carbon dioxide ice sublimates (vaporizes) in summer, revealing the surface, and freezes again in winter. As fall approaches, in each respective hemisphere, clouds begin to form over the polar region and the ice cap begins to grow. In spring, the polar caps recede...........Aside from ice, Mars' polar regions have some interesting geologic features. The north polar dune field is a vast concentration of sand dunes that stretches around the entire north polar cap. In some areas, the sand measures up to 500 km (300 miles) across. When the dunes begin to thaw in spring, dark spots form on their surfaces. The north polar dunes were first seen during the 1972 mapping of Mars by Mariner 9, and they are identical to dunes in Earth's desert regions..

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4 0
3 years ago
If 54 J of heat is added to an aluminum can with a mass of 23.3 g what is the temperature change
Katyanochek1 [597]
Temp change = Q/(mass x sph)
Temp change =57/(22 x .903)
Temp Change = 2.97 ∘C
Temp change 3.0 ∘C
3 0
3 years ago
On a 10 day wilderness expedition you'll need to heat 4.0kg of water to the boiling point each day. The air temperature will ave
const2013 [10]

Explanation:

It is known that relation between heat energy, mass and temperature change is as follows.

                q = mC \times \Delta T

where,   C = specific heat of water (in given case) = 4.184 kJ/kg ^{o}C

              m = mass

          \Delta T = change in temperature

Therefore, calculate the heat energy as follows.

              q = mC \times \Delta T

                 = 4 kg \times 4.184 kJ/kg^{o}C \times (100 - 25)^{o}C

                =  1255.2 kJ/day

For 10 days, total heat required is as follows.

                10 \times 1255.2

               = 12552 kJ

It is known that the value of standard enthalpy of combustion of butane is -49.5 kJ/g.

Therefore, combustion of 1 gm of butane will be 49.5 kJ. Hence, total amount of butane required will be as follows.

                  \frac{12552 kJ}{49.5 kJ/g}

                     = 253.57 g

As it is given that 1 canister of butane contains 75 g butane. Hence, no. of canisters required are as follows.

         No. of canisters required = \frac{253.57}{75}  

                                                    = 3.38

                                                    = 4 (approximately)

Thus, we can conclude that minimum number of fuel canisters you must bring are 4.

3 0
3 years ago
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