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2 years ago

In the presence of a base, blue litmus paper will .O turn purplestay blueto turn red

Chemistry

2 answers:

Inessa05 [86]2 years ago

7 0

Answer:

In the presence of a base, blue litmus paper will turn red........

Strike441 [17]2 years ago

5 0

Answer:

In the presence of a base the blue litmus paper would remain blue.

Explanation:

This is because the litmus paper will react depending on the pH of the solution added. If the solution is acidic pH < 7, the litmus paper will turn red. If the solution is basic, pH > 7 the litmus paper will turn blue. If the litmus paper is blue when a base is added it will remain blue.

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Sonbull [250]

Answer: option B. Poles

Explanation:

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3 years ago

How many atoms does 2.0 moles of He represent

Rudiy27

We use the following formula to calculate the number of atoms:

n (mol) = N(number of atoms) / NA

N(He) = n(mol) · NA

N(He) = 2,0 moles · 6.02·1023 = 12.04·1023 atoms

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3 years ago

Which of the following equations are correctly balanced

IRINA_888 [86]

Ion know yo but good luck

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2 years ago

Nitrogen dioxide (NO2) cannot be obtained in a pure form in the gas phase because it exists as a mixture of NO2 and N2O4. At 16°

Pavel [41]

Answer:

PNO₂ = 0.49 atm

PN₂O₄ = 0.45 atm

Explanation:

Let's begin with the equation of ideal gas, and derivate from it an equation that involves the density (ρ = m/V).

PV = nRT

n = m/M (m is the mass, and M the molar mass)

$PV = \frac{m}{M}RT$

$PxM = \frac{m}{V}RT$

PxM = ρRT

ρ = PxM/RT

With the density of the gas mixture, we can calculate the average of molar mass (Mavg), with the constant of the gases R = 0.082 atm.L/mol.K, and T = 16 + 273 = 289 K

$2.7 = \frac{0.94xMavg}{0.082x289}$

0.94Mavg = 63.9846

Mavg = 68.0687 g/mol

The molar mass of N is 14 g/mol and of O is 16 g/mol, than $M_{NO2} = 46$ g/mol and $M_{N2O4} = 96$ g/mol. Calling y the molar fraction:

$Mavg = M_{NO2}y_{NO2} + M_{N2O4}y_{N2O4}$

And,

$y_{NO2} + y_{N2O4} = 1$

$y_{N2O4} = 1 - y_{NO2}$

So,

$68.0687 = 46y_{NO2} + 92x(1 - y_{NO2})$

$68.0687 - 92 = 46y_{NO2} - 92y_{NO2}$

$46y_{NO2} = 23.9313$

$y_{NO2} = 0.52$

$y_{N2O4} = 0.48$

The partial pressure is the molar fraction multiplied by the total pressure so:

PNO₂ = 0.52x0.94 = 0.49 atm

PN₂O₄ = 0.48x0.94 = 0.45 atm

8 0

3 years ago

A student took a calibrated 250.0 gram mass, weighed it on a laboratory balance, and found it read 266.5 g. What was the student

marta [7]

Answer:

$\boxed{\text{6.60 \%}}$

Explanation:

$\text{Percent error} = \dfrac{\lvert \text{Measured - Actual}\lvert}{ \text{Actual}} \times100 \,\%$

$\text{\% error} = \dfrac{\lvert 266.5 - 250.0\lvert}{250.0} \times 100 \, \% = \dfrac{\lvert 16.5\lvert}{250.0} \times 100 \, \% = \dfrac{16.5}{250.0} \times 100 \,\%\\\\ = 0.0660 \times 100 \, \% = \textbf{6.60 \%}\\\text{The student's percent error is $\boxed{\textbf{6.60 \%}}$}$

4 0

3 years ago

In the presence of a base, blue litmus paper will .O turn purplestay blueto turn red​

In the presence of a base, blue litmus paper will .O turn purplestay blueto turn red