1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
GREYUIT [131]
3 years ago
8

Which process describes vaporization that takes place below the surface of a liquid?

Chemistry
2 answers:
NISA [10]3 years ago
6 0

 The correct answer is evaporation because Vaporization that takes place only on the surface of a liquid is called Evaporation.

*Hope this helps!

zimovet [89]3 years ago
5 0

Answer:

d

Explanation:

You might be interested in
PLEASE HURRY LIMITED TIME
Stolb23 [73]
3rd one sorry if it’s wrong
3 0
2 years ago
The variables _______ and ________ affect the gravitational force between objects.
anastassius [24]
I think the answer is A
5 0
3 years ago
Read 2 more answers
What would be needed for shale to form from slate
EastWind [94]
Shale actually forms in the part of the rock cycle called compaction.
7 0
3 years ago
Which of the following statements is true about the sense of smell? Men and women smell the same number of odors. The amount of
puteri [66]

Answer:

I think it is B

which I think is the correct answer

4 0
3 years ago
Read 2 more answers
Molybdenum (Mo) has a body centered cubic unit cell. The density of Mo is 10.28 g/cm3. Determine (a) the edge length of the unit
ser-zykov [4K]

<u>Answer:</u>

<u>For a:</u> The edge length of the unit cell is 314 pm

<u>For b:</u> The radius of the molybdenum atom is 135.9 pm

<u>Explanation:</u>

  • <u>For a:</u>

To calculate the edge length for given density of metal, we use the equation:

\rho=\frac{Z\times M}{N_{A}\times a^{3}}

where,

\rho = density = 10.28g/cm^3

Z = number of atom in unit cell = 2  (BCC)

M = atomic mass of metal (molybdenum) = 95.94 g/mol

N_{A} = Avogadro's number = 6.022\times 10^{23}

a = edge length of unit cell =?

Putting values in above equation, we get:

10.28=\frac{2\times 95.94}{6.022\times 10^{23}\times (a)^3}\\\\a^3=\frac{2\times 95.94}{6.022\times 10^{23}\times 10.28}=3.099\times 10^{-23}\\\\a=\sqrt[3]{3.099\times 10^{-23}}=3.14\times 10^{-8}cm=314pm

Conversion factor used:  1cm=10^{10}pm  

Hence, the edge length of the unit cell is 314 pm

  • <u>For b:</u>

To calculate the edge length, we use the relation between the radius and edge length for BCC lattice:

R=\frac{\sqrt{3}a}{4}

where,

R = radius of the lattice = ?

a = edge length = 314 pm

Putting values in above equation, we get:

R=\frac{\sqrt{3}\times 314}{4}=135.9pm

Hence, the radius of the molybdenum atom is 135.9 pm

4 0
3 years ago
Other questions:
  • Apply the ideal gas law to solve problems
    14·1 answer
  • A material has a density of 8.9 g/cm^3. You have 3 grams of the substance. How much space does it take up?
    12·1 answer
  • BRAINLIESTTT ASAP!! PLEASE HELP ME :)<br><br> How do particles become ions?
    12·2 answers
  • How to assign oxidation and reduction numbers
    15·1 answer
  • How many resonance structures are possible for hydroxide ion?<br> A. 3<br> B. none<br> C. 2
    13·1 answer
  • How many electrons do atoms usually want in their outermost orbital?(Octet Rule)​
    10·1 answer
  • Please help me people it’s due today at 6:00pm please help me please please
    7·2 answers
  • Hi do you know this?​
    15·2 answers
  • PLEASE HELP PLEASE HELP PLEASE HELP PLEASE HELP PLEASE HELP PLEASE HELP PLEASE HELP PLEASE HELP PLEASE HELP PLEASE HELP PLEASE H
    7·1 answer
  • ¿Cómo puedes conocer tu condición física?
    10·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!