3 - 0,

Multiplication in GF(24 ): Compute A(x)B(x) mod P(x) in GF(24 ) using the irreducible polynomial P(x) = x 4 + x + 1, where A(x)

tankabanditka [31]

Answer:

Step-by-step explanation:

hello,

i advice you check the question again if it is GF( $2^{4}$ ) or GF(24). i believe the question should rather be in this form;

multiplication in GF( $2^{4}$ ): Compute A(x)B(x) mod P(x) = $x^{4}$ + $x$ +1, where A(x)= $x^{2}$ +1, and B(x)= $x^{3} + x+1$ .

i will solve the above question and i believe with this you will be able to solve any related problem.

A(x)B(x)= $(x^{2} +1) (x^{3}+x+1) mod (x^{4}+x+1 ) = (x^{5} +x^{3}+x^{2} ) + (x^{3}+x+1 ) mod (x^{4} + x+1 )$

= $x^{5}+2x^{3} +x^{2} + x + 1 mod(x^{4}+x+1 )$

= $2x^{2} +1$

please note that the division by the modulus above we used

$\frac{x^{5}+2x^{3}+x^{2} +1 }{x^{4}+x+1}= x+\frac{2x^{3} +1}{x^{4}+x+1}$

5 0

3 years ago

Explain how the position of the decimal point changes in a quotient as you divide by increasing powers of 10.

Darya [45]

The decimal adds a zero every time the powers of ten increase for example if u do 1 x $10^{2}$ =100 if u do 1x $10x^{3}$ =1,000

3 0

3 years ago

Pls help me plssssss

scoray [572]

Answer:

1

Step-by-step explanation:

It's the correct spelling.

8 0

2 years ago

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If the temperature is 7 degrees below zero and then rises 3 degrees,will the final temperature be positive or negative

sladkih [1.3K]

It would be negative cz it would add up to -4

6 0

2 years ago

Read 2 more answers

1. What is an equation for the line with slope 2/3 and y-intercept 9?

Monica [59]

Question 1:

The generic equation of the line is given by:
$y = mx + b
$
Where,
m: slope of the line
b: cutting point with the y axis
Substituting values we have:
$y = \frac{2}3}x + 9
$
Answer:
an equation for the line with slope 2/3 and y-intercept is:
$y = \frac{2}3}x + 9$

Question 2:

The standard equation of the line is given by:
$y-yo = m (x-xo)
$
Where,
m: slope of the line
(xo, yo): ordered pair that belongs to the line
The slope of the line is:
$m = \frac{y2-y1}{x2-x1}$
Substituting values:
$m = \frac{1-(-3)}{3-1}$
$m = \frac{1+3}{3-1}$
$m = \frac{4}{2}$
$m = 2
$
We choose an ordered pair:
$(xo, yo) = (3, 1)
$
Substituting values:
$y-1 = 2 (x-3)
$
Rewriting:
$y = 2x - 6 + 1

y = 2x - 5$
Answer:
An equation in slope-intercept form for the line that passes through the points (1, -3) and (3,1) is:
$y = 2x - 5
$

Question 3:

For this case, since the variation is direct, then we have an equation of the form:
$y = kx
$ Where,
k: constant of variation.
We then have the following equation:
$-4y = 8x
$ Rewriting we have:
$y = \frac{8}{-4}x
$
$y = -2x
$ Therefore, the constate of variation is given by:
$k = -2
$
Answer:
the constant of variation is:
$k = -2$

Question 4:

For this case, since the variation is direct, then we have an equation of the form:
$y = kx
$ Where,
k: constant of variation.
We must find the constant k, for this we use the following data:
y = 24 when x = 8
Substituting values:
$24 = k8
$ Clearing k we have:
$k = \frac{24}{8} 
$
$k = 3
$
Therefore, the equation is:
$y = 3x
$ Thus, substituting x = 10 we have that the value of y is given by:
$y = 3 (10)

y = 30$ Answer:
the value of y when x = 10 is:
$y = 30$

6 0

3 years ago

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