Answer:
The average cost of each dinner at Dave's party is <u>$5.79</u>.
Step-by-step explanation:
Given:
Dave ordered dinner for a party of 10 people.
Three people ordered the $4.75 chicken dinner, two people ordered the $4.95 fish dinner, and five had the beef dinner at a cost of $6.75 each.
Now, to find the average cost of each dinner at Dave's party.
So, we get the total amount for the dinner:
Three people ordered the $4.75 chicken dinner.

Two people ordered the $4.95 fish dinner.

Five had the beef dinner at a cost of $6.75.

Total amount of dinner = 
Now, to get the average cost of each dinner of 10 people we divide the total amount of dinner by 10:


Therefore, the average cost of each dinner at Dave's party is $5.79.
We need to convert 2 kilograms into pounds. First, we find how many pounds are in 1 kilogram.
There are about 2 pounds in one kilogram.
Then we multiply 2 pounds by 2 kilograms to convert the 2 kilograms into pounds.
2 * 2 = 4
So, the answer to this question is 4 pounds.
7 and 1/3 so 7 1/3
Hope this helps
Answer:19
Step-by-step explanation:
−1+(
4
2
(6−1))(2)
=−1+2(6−1)(2)
=−1+(2)(5)(2)
=−1+(10)(2)
=−1+20
=19