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babunello [35]
3 years ago
14

The probability of a certain brand of battery going dead within 15 hours is 1/3. Noah has a toy that requires 4 of these batteri

es. He wants to simulate the situation to estimate the probability that at least one battery will die before 15 hours are up.
After doing the simulation 5 times, Noah has the following results. What should he use as an estimate of the probability that at least one battery will die within 15 hours?

Mathematics
1 answer:
Leona [35]3 years ago
4 0

Answer:

He should estimate with just a normal time.

Step-by-step explanation:

he should estimate with time because if you takes a couple of hours and then with another point of hours he could end up with his answer for his research and his questions

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What are the values of x and y?
adoni [48]

Answer:

Step-by-step explanation:

hello :

use pytagor-rule :

triangle ABC : (x+15)² =17²+y²....(*)

triangle BDC : y² = x²+8²....(**)

by (**) put the value of y² in (*) :

(x+15)² = 17²+x²+8²

x²+30x+15² = 17²+x²+18²

30x +225 = 289+64

30x = 128

x= 128/30

x= 64/15

put this value in (**) calculate y²  ......continu

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4 years ago
Please answer thank you
mariarad [96]

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3 years ago
What are the zeros of f(x) = x2 - x - 30?
Grace [21]

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Which of the following is NOT true?
ArbitrLikvidat [17]

A., B., C., D., are NOT true. I think this is a trick question. Lol

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3 years ago
50 POINTS
user100 [1]

\huge \sf༆ Answer ༄

According to the question ;

{ \qquad{ \sf{ \dashrightarrow}}}  \:  \: \sf \:y \propto x

Now, let's add a constant of proportionality to replace proportionality sign with equal to :

{ \qquad{ \sf{ \dashrightarrow}}}  \:  \: \sf \:y = kx

[ where, k is proportionality constant ]

plug the value of x and y from any ordered pair in the table , for example : \sf(\dfrac{1}{5} , 2)

{ \qquad{ \sf{ \dashrightarrow}}}  \:  \: \sf \:2 = k \times  \dfrac{1}{5}

{ \qquad{ \sf{ \dashrightarrow}}}  \:  \: \sf \:k = 2 \times 5

{ \qquad{ \sf{ \dashrightarrow}}}  \:  \: \sf \:k = 10

Therefore, value of proportionality constant (k) is

\overbrace{  \underbrace{\underline{ \boxed{ \sf 10 }}}}

5 0
3 years ago
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