Engineering ethics is not without abstraction, but in contrast with computing, it is animated by a robust and active movement concerned with the seamless identification of ethics with practice.
<h3 /><h3>What is engineering?</h3>
This is a branch of science and technology concerned with the design, building, and use of engines, machines, and structures that uses scientific principles.
Comparing ethics in engineering and ethics in computing:
- Engineering ethics are a set of rules and guidelines. While computing ethics deals with procedures, values and practices.
- In engineering ethics, engineers must adhere to these rules as a moral obligation to their profession While in computing ethics, the ethics govern the process of consuming computer technology.
- Following these ethics for the two professions will NOT cause damage, but disobeying them causes damage.
Some practical examples in the computing field:
- Avoid using the computer to harm other people such as creating a bomb or destroying other people's work.
- Users also should not use a computer for stealing activities like breaking into a bank or company.
- Make sure a copy of the software had been paid for by the users before it is used.
Some practical examples in the engineering field:
- Integrity for oneself.
- Respect for one another.
- Pursuit of excellence and accountability.
Hence, Engineering ethics is the field of system of moral principles that apply to the practice of engineering and following them is important to the profession.
Read more about <em>engineering</em> here:
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Answer:
The provided length of the vertical curve is satisfactory for the reconstruction design speed of 60 mi/h
Explanation:
The explanation is shown on the first uploaded image
Answer:
18 kJ
Explanation:
Given:
Initial volume of air = 0.05 m³
Initial pressure = 60 kPa
Final volume = 0.2 m³
Final pressure = 180 kPa
Now,
the Work done by air will be calculated as:
Work Done = Average pressure × Change in volume
thus,
Average pressure =
= 120 kPa
and,
Change in volume = Final volume - Initial Volume = 0.2 - 0.05 = 0.15 m³
Therefore,
the work done = 120 × 0.15 = 18 kJ
Answer:
850.8480103 feet
Explanation:
First you take the diameter and find the circumference, which is (2)(pi)(r) plug in your r which is 26/2= 13 so 2(13)(pi) and multiply taht by 125 after that take your answer and divide by 12which is 850.8480103