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SIZIF [17.4K]
4 years ago
15

Basil is installing a system in Toronto, Ontario where they are wide temperature variations. What is the TD of the system he’s i

nstalling here where the outdoor design temperature is 20 f and the indoor design is 70 f
Engineering
1 answer:
marysya [2.9K]4 years ago
4 0
In places with cold winters, space heating systems have a fundamental role in buildings. Without them, indoor temperatures would quickly become unsuitable for human occupancy. The local weather is one of the most important factors when designing a heating system; if two identical buildings are developed in Miami FL and New York City, the heating load will be much higher for the NYC property.

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A rigid, insulated tank that is initially evacuated is connected through a valve to a supply line that carries helium at 200 kPa
Aleks04 [339]

Answer: a 8143.71 kJ/kg

b 393.15 K

Explanation:

This system is an isobaric process in which there is no change in pressure a quasistatic process where a pressure distribution exists

a since no change in pressure =0 the system does work thus

FOR HELIUM  properties in standard thermodynamic chart

cv = 3.1 kJ/kgK

M = Molar mass = 4 kg/kmol

R = Universal gas constant = 8.314 kJ/kg K

cp ≈ cv +R /M = 3.1 + 8.314 /4 = 5.1785 kJ/kgK  

Cp = cp * M = 5.1785 kJ/kgK * 4 kg/kmol  = 20.714 kJ/kgkmol

T = 120  °C  to Kelvin = 120 + 273.15k = 393.15 K

W =n Cp ΔT = 1 kmol * 20.714 kJ/kg kmol* 393.15 K = 8143.71 kJ/kg

b convert T °C = T K thus 120 + 273.15 K = 393.15 K

P₁/T₁ = P₂/T₂

200 kPa/ 393.15 K = 200 kPa/T₂

T₂ = 200 kPa * 393.15 K/ 200 kPa = 393.15 K or 120 k

7 0
4 years ago
What type of engineer is responsible for the protection of wetlands and beaches?
vovikov84 [41]
Environment engineer
4 0
3 years ago
Read 2 more answers
Consider the flow field given by V ! =xy2^i− 1 3 y3^j+xyk ^. Determine (a) the number of dimensions of the flow, (b) if it is a
Basile [38]

Answer:

a) The flow has three dimensions (3 coordinates).

b) ∇V = 0 it is a incompressible flow.

c) ap = (16/3) i + (32/3) j + (16/3) k

Explanation:

Given

V = xy² i − (1/3) y³ j + xy k

a) The flow has three dimensions (3 coordinates).

b) ∇V = 0

then

∇V = ∂(xy²)/∂x + ∂(− (1/3) y³)/∂y + ∂(xy)/∂z

⇒ ∇V = y² - y² + 0 = 0 it is a incompressible flow.

c) ap = xy²*∂(V)/∂x − (1/3) y³*∂(V)/∂y + xy*∂(V)/∂z

⇒ ap = xy²*(y² i + y k) - (1/3) y³*(2xy i − y² j + x k) + xy*(0)

⇒ ap = (xy⁴ - (2/3) xy⁴) i + (1/3) y⁵ j + (xy³ - (1/3) xy³) k

⇒ ap = (1/3) xy⁴ i + (1/3) y⁵ j + (2/3) xy³ k

At point (1, 2, 3)

⇒ ap = (1/3) (1*2⁴) i + (1/3) (2)⁵ j + (2/3) (1*2³) k

⇒ ap = (16/3) i + (32/3) j + (16/3) k

3 0
3 years ago
Consider a 8-m-long, 8-m-wide, and 2-m-high aboveground swimming pool that is filled with water to the rim. (a) Determine the hy
Stolb23 [73]

Answer:

The hydrostatic force of 313920 N is acted on each wall of the swimming pool and this force is acted at 1 m from the ground. The hydrostatic force is quadruple if the height of the walls is doubled.

<u>Explanation:</u>

To calculate force on the walls of swimming pool whose dimensions are given as <em>8-m-long, 8-m-wide, and 2-m-high</em>. We know that formula for hydrostatic force is \text {hydrostatic force}=\text {pressure} \times \text {area,}=\rho g h \times(l \times h)  

\equiv \rho g h^{2} l, we know ρ=density of fluid=1000 g / c m^{3},

g=acceleration due to gravity=9.81 m / s^{2}, h=height of the pool=2 m and l=length of the pool=8 m.  

hydrostatic force on each wall=1000 \times 9.81 \times 2^{2} \times 8 = 313920 N.

<em>The distance at which hydrostatic force is acted is half of the height of the swimming pool. </em>

At 1 m from the ground this hydrostatic force is acted on each wall.  

The force is <em>quadruple if the height of the walls of the pool is doubled</em> this is because, the<em> height is doubled and taken as h=4 m</em> and substitute in the equation =\rho g h^{2} l = 1000 \times 9.81 \times 4^{2} \times 8 = 1255680 N. This is 4 times 313920 N.

5 0
3 years ago
A heat exchanger takes compressed liquid water and converts it into steam with a temperature and pressure of 20 Mpa and 480 C; r
belka [17]

Answer:

See explaination

Explanation:

Lets first consider the term Isentropic efficiency. The isentropic efficiency of a compressor or pump is defined as the ratio of the work input to an isentropic process, to the work input to the actual process between the same inlet and exit pressures. IN practice, compressors are intentionally cooled to minimize the work input.

Please kindly check attachment for the step by step solution of the given problem.

6 0
3 years ago
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