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Svet_ta [14]
2 years ago
14

Rotating magnetic field inside a set of conducting wires is a simple description of a what

Engineering
1 answer:
Advocard [28]2 years ago
5 0

Answer:

hii there

It is called an electromagnet. The strength of the magnetic field produced is determined by the amount of current passing through the conductor. The rotating magnetic field is the rotor and the windings in which current is produced are in the fixed stator.

Explanation:

hope it helps

have a nice day : )

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You are asked to design a software package for an On-line Banking System (OBS). The OBS will take requests from its user on the
Anit [1.1K]

Answer:

From the statements described above,The proposed software package Online Banking System(OBS) shall provide the following services to the customer(account holder)

Receive all transaction requests from the customers trough online to perform banking activities

Offer a variety of services in banking like:

Opening an account with facilities of Savings,Checking and CD

Issuing checks and check clearance

Transfer of funds between savings and checking account

Establishing a CD(Certificate of Deposit)

Performing routine activities like

Deposit or withdraw funds from a checking account

Closing an account in one of the following operation

Complete closure of account

Closing only savings account

Withdraw CD (on Maturity of CD deposits) and close CD account

Unlike traditional Banking system, OBS offers all the operations through On-line mode over the internet thereby it eliminates manual intervention for the banking transactions from the Bank's side for most of the transactions except some cases like verification of new account applications or complaint redressal and technical support .In such cases ,There will be some users of the software with special privileges to access certain services to perform activities like user data verification and technical support.

Step:1 Identification of actors and software entities for the system to be implemented

The following are the actors identified in the system

Actors:

The users of the proposed system were classified as:

Customer : A user with an active account

Guest user:The user who applies for an account

Administrator:Maintainsand Controls OBS

Manager: Manages the transactions and Banking related issues

Technical Manager: Resolves technical issues of customers

Software entities:

Bank database :Maintains the data of all user accounts

Application server : Maintains the application software components and hosts the OBS website

Automatic Clearing House system : Processes transactions for checks

Step 2: Designing use cases

Use case diagrams are used to describe the system model by representing a set of use cases .Each use case represents a set of actions performed on the system by an actor.

The following are the two approaches of representing the system in a use case model:

1.Representing a use case for actions done by actors e.g. login , logout,message etc.,

2.Representing a use case for business process(Business use cases) e.g. transfer,registration etc.,

The following is the description of five possible business use cases for the requirements specified above

3 0
3 years ago
• What are some methods currently used to unclog arteries and keep them clear?
topjm [15]
Good fats are also called unsaturated fats. They're found in foods like olives, nuts, avocado, and fish. Cut sources of saturated fat, such as fatty meat and dairy. Choose lean cuts of meat, and try eating more plant-based meals.
5 0
3 years ago
6. Find the heat flow in 24 hours through a refrigerator door 30.0" x 58.0" insulated with cellulose fiber 2.0" thick. The tempe
Ilia_Sergeevich [38]

Answer:

The heat flow in 24 hours through the refrigerator door is approximately 1,608.57 BTU

Explanation:

The given parameters are;

The duration of the heat transfer, t = 24 hours = 86,400 seconds

The area of the refrigerator door, A = 30.0" × 58.0" = 1,740 in.² = 1.122578 m²

The material of the insulator in the door = Cellulose fiber

The thickness of the insulator in the door, d = 2.0" = 0.0508 m

The temperature inside the fridge = 38° F = 276.4833 K

The temperature of the room = 78°F = 298.7056 K

The thermal conductivity of cellulose fiber = 0.040 W/(m·K)

By Fourier's law, the heat flow through a by conduction material is given by the following formula;

\dfrac{Q}{t} = \dfrac{k \cdot A \cdot (T_2 - T_1) }{d}

Q = \dfrac{k \cdot A \cdot (T_2 - T_1) }{d} \times t

Therefore, we have;

Q = \dfrac{0.04 \times 1.122578 \times (298.7056 - 276.4833 ) }{0.0508} \times 86,400 =1,697,131.73522

The heat flow in 24 hours through the refrigerator door, Q = 1,697,131.73522 J = 1,608.5705140685 BTU

7 0
2 years ago
A circular bar will be subjected to an axial force (P) of 2000 lbf. The bar will be made of material that has a strength (S) of
schepotkina [342]

Answer:

n = 2.36

Explanation:

The stress experimented by the circular bar is:

\sigma = \left[\frac{2000\, lbf}{\frac{\pi}{4}\cdot (0.5\,in)^{2}}\right]\cdot \left(\frac{1\,kpsi}{1000\,psi} \right)

\sigma = 10.186\,kpsi

The safety factor is:

n = \frac{24\,kpsi}{10.186\,kpsi}

n = 2.36

5 0
3 years ago
A pump with a power of 5 kW (pump power, and not useful pump power) and an efficiency of 72 percent is used to pump water from a
almond37 [142]

Answer:

a) The mass flow rate of water is 14.683 kilograms per second.

b) The pressure difference across the pump is 245.175 kilopascals.

Explanation:

a) Let suppose that pump works at steady state. The mass flow rate of the water (\dot m), in kilograms per second, is determined by following formula:

\dot m = \frac{\eta \cdot \dot W}{g\cdot H} (1)

Where:

\dot W - Pump power, in watts.

\eta - Efficiency, no unit.

g - Gravitational acceleration, in meters per square second.

H - Hydrostatic column, in meters.

If we know that \eta = 0.72, \dot W = 5000\,W, g = 9.807\,\frac{m}{s^{2}} and H = 25\,m, then the mass flow rate of water is:

\dot m = 14.683\,\frac{kg}{s}

The mass flow rate of water is 14.683 kilograms per second.

b) The pressure difference across the pump (\Delta P), in pascals, is determined by this equation:

\Delta P = \rho\cdot g\cdot H (2)

Where \rho is the density of water, in kilograms per cubic meter.

If we know that \rho = 1000\,\frac{kg}{m^{3}}, g = 9.807\,\frac{m}{s^{2}} and H = 25\,m, then the pressure difference is:

\Delta P = 245175\,Pa

The pressure difference across the pump is 245.175 kilopascals.

4 0
3 years ago
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