When 5.0 mol Al react with 13 mol HCl, what is the limiting reactant, and how many moles of AlCl3 can be formed? 2Al + 6HCl → 2A
1 answer:
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Answer:
Explanation:
= Initial pressure = 200 kPa
= Final pressure
= Initial temperature =
= Final temperature =
We have the relation
The pressure that would be exerted after the temperature change is .
Answer:
Change in volume on changing temperature from 33 to 5
is 5.49 mL
Explanation:
Initial volume of gas = V = 60 mL
Assuming final volume of gas to be V' mL
Initial temperature = T = 33 = 306 K
Final temperature = T' = 5 = 278 K
The relationship between volume and temperature of gas at constant pressure is shown below
Change in volume on changing temperature = 5.49 mL