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3 years ago

5

Manuel has 18 yards of fabric to make table runners. It takes 3/4 of a yard to make each runner. The expression that represents

the amount of fabric left after making t table runners is 18 - 3/4 t. Which are possible runners that Manuel could make? Select three options.
20

22

24

26

28

2 answers:

prohojiy [21]3 years ago

8 0

Answer:

20

22

24

Step-by-step explanation:

To determine the maximum number of runners that Manuel could make take the amount of cloth and divide by 3/4

18 ÷ 3/4

Copy dot flip

18 * 4/3

18/3 *4

6*4

24

He can make less than or equal to 24

Sergio039 [100]3 years ago

4 0

Answer:

20, 22, 24

Step-by-step explanation:

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Carlos walk to school on the 14th of 20 days in February which value is equivalent to the fraction of school days in February th

Lady bird [3.3K]

Answer:

$\dfrac{7}{10}$

Step-by-step explanation:

Given that,

Carlos walk to school on the 14th of 20 days in February.

We need to find the equivalent to the fraction of school days in February that Carlos walk to school.

Required percentage is given by :

$\%=\dfrac{14}{20}\times 100\\\\=14\times 5\\\\=70\%$

or

$=\dfrac{7}{10}$

So, the required fraction is equal to $\dfrac{7}{10}$ .

6 0

2 years ago

x2y - 2xy - 24y = y(x2 - 2x - 24) What is the completely factored form of x2y – 2xy – 24y? (xy + 4)(x – 6) xy(x + 4)(x – 6) y(x

likoan [24]

we are given

$x^2y-2xy-24y=y(x^2-2x-24)$

now, we can factor out right side term

$x^2-2x-24=x^2-6x+4x-6*4$

$x^2-2x-24=(x-6)(x+4)$

now, we can plug back

and we get

so,

$x^2y-2xy-24y=y(x-6)(x+4)$ .............Answer

5 0

3 years ago

Read 2 more answers

Which are the solutions of x^2 = –11x + 4?

strojnjashka [21]

This is a quadratic equation, i.e. an equation involving a polynomial of degree 2. To solve them, you must rearrange them first, so that all terms are on the same side, so we get

$x^2 + 11x - 4 = 0$

i.e. now we're looking for the roots of the polynomial. To find them, we can use the following formula:

$x_{1,2} = \frac{-b\pm\sqrt{b^2-4ac}}{2}$

where $x_{1,2}$ is a compact way to indicate both solutions $x_1$ and $x_2$ , while $a,b,c$ are the coefficients of the quadratic equation, i.e. we consider the polynomial $ax^2+bx+c$ .

So, in your case, we have $a=1,\ \ b=11,\ \ c=-4$

Plug those values into the formula to get

$x_{1,2} = \frac{-11\pm\sqrt{121+16}}{2} = \frac{-11\pm\sqrt{137}}{2}$

So, the two solutions are

$x_1 = \frac{-11+\sqrt{137}}{2}$

$x_2 = \frac{-11-\sqrt{137}}{2}$

3 0

3 years ago

Shawn earns $10 per hour for the first 32 hours he works in a week. For any additional

olchik [2.2K]

Answer:

im sorry im not sure but i think 9

Step-by-step explanation:

5 0

3 years ago

PLEASE HELP! A) 6,135º C B) 6,681º C C) 502º C D) 47º C

Arada [10]

Answer: 47°C

Step-by-step explanation:

Since we are given the velocity, all we have to do is plug in 358 for v and solve for t.

$358=20\sqrt{273+t}$ [divide both sides by 20]

$17.9=\sqrt{273+t}$ [square both sides to cancel out square root]

$320.41=273+t$ [subtract both sides by 273]

$t=47.41$

Now that we know the temperature is 47.41°C, we know our answer choice is D.

8 0

3 years ago