Answer:
Given that
speed u=4*10^6 m/s
electric field E=4*10^3 N/c
distance b/w the plates d=2 cm
basing on the concept of the electrostatices
now we find the acceleration b/w the plates to find the horizontal distance traveled by the electron when it hits the plate.
acceleration a=qE/m=
=
m/s
now we find the horizontal distance traveled by electrons hit the plates
horizontal distance
![X=u[2y/a]^{1/2}](https://tex.z-dn.net/?f=X%3Du%5B2y%2Fa%5D%5E%7B1%2F2%7D)
=![4*10^6[2*2*10^{-2}/7*10^{14}]^{1/2}](https://tex.z-dn.net/?f=4%2A10%5E6%5B2%2A2%2A10%5E%7B-2%7D%2F7%2A10%5E%7B14%7D%5D%5E%7B1%2F2%7D)
=
= 3 cm
Explanation:
PRIMERO ENCUENTRAS EL PESO DEL PARACAIDISTA
= 65 kg(
) = 637 N
CON LA FÓRMULA DE LA ENERGÍA POTENCIAL
U = 637 N(6000 m - 3500 m) = 1592500 J
Answer: Search Results
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Answer: Surface waves can have characteristics of both longitudinal and transverse waves in the following way; The motion of the surface waves is up and down which is perpendicular to the direction of the wave. This is similar to the motion of transverse waves whereas the the motion of longitudinal.
Explanation:
Answer:
When the voltage is at a maximum positive value, the the current is at a value that is maximum and positive
Explanation:
We know that the relation between the Voltage and the current is given using the Ohm's law, which states that the voltage (V) is directly proportional to the current (I)
Mathematically,
V ∝ I
Hence,
When the voltage is at a maximum positive value, the the current is at a value that is maximum and positive
