If a circle was flattened by pushing down on it, it would most likely form into the shape of ----------- which has ----------- f
ocal points.
2 answers:
Answer:If a circle was flattened by pushing down on it, it would most likely form into the shape of <em><u>ellipse </u></em>which has <em><u>two </u></em>focal points.
Explanation:
Ellipse is curve in a plane with two focus points. The sum of the distance of one point from both fixed points or focal points in the plane remain constant.
When circle was flattened by pushing it deform to plane shape likely to the shape of ellipse.
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Answer:
Vc = 2.41 v
Explanation:
voltage (v) = 16 v
find the voltage between the ends of the copper rods .
applying the voltage divider theorem
Vc = V x ()
where
- Rc = resistance of copper =
(l = length , a = area, ρ = resistivity of copper)
- Ri = resistance of iron =
(l = length , a = area, ρ₀ = resistivity of copper)
Vc = V x ()
Vc = V x ()
Vc = V x ()
where
- ρ = resistivity of copper = 1.72 x 10^{-8} ohm.meter
- ρ₀ = resistivity of iron = 9.71 x 10^{-8} ohm.meter
Vc = 16 x ()
Vc = 2.41 v
The reasoning is wrong if we look into Newton's Law of gravitation.
Newton's law of gravitation states that every particle in the universe attracts every other particle with a force that is directly proportional to the product of their masses and inversely proportional to the square of the distance between their centers.
The law is written as follows;
The distance between the two particles, is a function of force and their masses not necessarily time of motion.
In the given problem only time of motion was considered which is wrong.
Thus, the reasoning is wrong if we look into Newton's Law of gravitation.
Learn more here: brainly.com/question/19680441