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maria [59]
4 years ago
5

If a circle was flattened by pushing down on it, it would most likely form into the shape of ----------- which has ----------- f

ocal points.

Physics
2 answers:
murzikaleks [220]4 years ago
8 0
The question is looking for "ellipse" and "two" to fill in the blanks.
labwork [276]4 years ago
5 0

Answer:If a circle was flattened by pushing down on it, it would most likely form into the shape of <em><u>ellipse  </u></em>which has <em><u>two </u></em>focal points.

Explanation:

Ellipse is curve in a plane with two focus points. The sum of the distance of  one point from both fixed points or focal points in the plane remain constant.

When circle was flattened by pushing it deform to plane shape likely to the shape of ellipse.

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A metal sphere of radius 2.0 cm carries an excess charge of 3.0 μC. What is the electric field 6.0 cm from the center of the sph
Nonamiya [84]

Answer:

The electric field is  E = 7.5 *10^{6} \ N/C

Explanation:

From the question we are told that

    The radius of the metal sphere is  R = 2.0 \ cm  =  0.02 \ m

     The excess charge which the metal sphere carries is  q =  3.0 \mu C  =  3.0*10^{-6} \ C

      The distance of the position being to the center is D = 6.0 \ cm  = 0.06 \ m

       The coulomb constant is   k =9*10^{9} \  N \cdot m^2 /C^2

Generally the electric field is mathematically represented as  

        E = \frac{k *  q}{D^2}

substituting values

        E = \frac{9*10^{9} *  30.*10^{-6}}{(0.06)^2}

      E = 7.5 *10^{6} \ N/C

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3 years ago
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notsponge [240]
Long phrase is the blank
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4 years ago
a jet plane traveling 1890 km/h pulls out of a dive by moving in an arc of radius 5.20km. what is planes acceleration in g's
Andrew [12]

Answer:

53 m/s^2

Explanation:

Unit conversions:

1890 km/h = 1890 km/h * 1000m/km * 1/3600 h/s = 525 m/s

5.2 km = 5200 m

Assume that the jets is traveling in perfect circular motion, we can calculate the centripetal acceleration of the motion:

a = \frac{v^2}{r}

where v = 525m/s is the velocity of the jet and r = 5200 is the radius of the arc

a = \frac{525^2}{5200} = 53m/s^2

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Answer:

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