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SpyIntel [72]
3 years ago
15

(HELP!! 10pts) a train travels 75km in 1hr, and then 68km in 2hrs. what is its average speed?

Physics
1 answer:
blondinia [14]3 years ago
8 0
Average speed = total distance travelled ÷ total time taken

AS = (75km + 68km) ÷ (1hr + 2hr)

As = 143km ÷ 3hr

AS = 47.66667 km/hr

AS = 47.7 km/hr (3sf)
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A 3.8kw elective motor powers an inclined conveyer belt. It is designed to lift heavy boxes from the warehouse floor to loading
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See the answers below

Explanation:

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a)

The function of the conveyor belt is to carry the boxes from an initial point that is at low altitude to an end point that is at high altitude. In this way the conveyor belt prints a speed to the box to be able to raise it to the required vertical distance.

Since we have a velocity at the beginning and then we place the box at a high position, where then the box remains at rest, we can say that it converts kinetic energy to potential energy.

b)

Power is defined as the relationship of work over time. Therefore we have:

P=W/t

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t = time = 14 [s]

W=P*t\\W=3800*14\\W= 53200[J] = 53.2[kJ]

c)

Since the given time is equal to the given time at Point b, we can use the same work calculated.

We know that work is defined as the product of force by the distance traveled.

W =F*d

So, the force is equal to:

F=W/d\\F=53200/5.3\\F=10037.73[N]

Now we know that force is defined as the product of mass by gravitation acceleration.

F =m*g

where:

F = force or weight = 10037.73 [N]

g = gravity acceleration = 9.81 [m/s²]

m = mass [kg]

m=F/g\\m = 10037.73/9.81\\m = 1023.2 [kg]

d)

This part can be solved by means of the energy conservation theorem, where the potential energy is transformed into kinetic energy or vice versa.

E_{pot}=m*g*h = E_{kin}=0.5*m*v^{2}

where:

h = elevation = 4.7 [m]

v = velocity [m/s]

m*g*h=0.5*m*v^{2}\\g*h=0.5*v^{2} \\v=\sqrt{\frac{g*h}{0.5} } \\v=\sqrt{\frac{9.81*4.7}{0.5} }   \\v = 9.6 [m/s]

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