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3 years ago

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A virus has a mass of 9.0 x 10^-12 mg and an oil tanker has a mass of 3.0 x 10^7 kg. Use this information to answer the question

s below. Be sure your answer have the correct number of significant digits. How many moles of viruses have a mass equal to the mass of an oil tanker?

1 answer:

Alisiya [41]3 years ago

7 0

Answer:

The 5.53 moles of virus in an oil tanker.

Explanation:

Given:

Mass of virus $m = 9 \times 10^{-12}$ mg

Mass of oil $M = 3 \times 10^{7}$ kg

From the formula of moles,

Moles of viruses is given by,

Mass of 1 oil tanker divide by mass of 1 mole of virus,

$= \frac{3 \times 10^{7} } {9 \times 10^{-12} \times 6.022 \times 10^{23} \times 10^{-6} }$

$= 5.53$

Therefore, the 5.53 moles of virus in an oil tanker.

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Answer:54.70 N

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Note: I assume the mirror is concave, so that its focal length is positive (it is not specified in the text)

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Rearranging the equation, we find
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where $h_i$ is the heigth of the image and $h_o=1 cm$ is the height of the object. By rearranging the equation and using p and q, we find
$h_i=-h_o \frac{p}{q}=-(1 cm) \frac{10 cm}{10 cm}=-1 cm$
and the negative sign means the image is inverted.

2) As before, we can find the distance of the image from the mirror by using the mirror equation:
$\frac{1}{f}= \frac{1}{p}+ \frac{1}{q}$
Rearranging it, we find
$\frac{1}{q}= \frac{1}{f}- \frac{1}{p}= \frac{1}{2}- \frac{1}{10}= \frac{4}{10 cm}$
so, the distance of the image from the mirror is
$q= \frac{10}{4}cm= 2.5 cm$

3) As before, we find the distance of the image from the mirror by using the mirror equation:
$\frac{1}{f}= \frac{1}{p}+ \frac{1}{q}$
Rearranging it, we find
$\frac{1}{q}= \frac{1}{f}- \frac{1}{p}= \frac{1}{2}- \frac{1}{10}= \frac{4}{10 cm}$
so, the distance of the image from the mirror is
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And now we can use the magnification equation to find the image height:
$\frac{h_i}{h_o}=- \frac{p}{q}$
Rearranging it, we find
$h_i=-h_o \frac{p}{q}=-(3cm) \frac{10 cm}{2.5 cm}=-12 cm$
and the negative sign means the image is inverted.

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3 years ago