If the intermolecular forces in a liquid<span> are small, the molecules can easily escape from the surface of the</span>liquid<span>. The </span>liquid<span> will have a high </span>vapour pressure<span>. The normal </span>boiling point<span> is the temperature in which the </span>vapour pressure of a liquid<span> becomes equal to atmospheric </span>pressure<span>.</span>
Answer:
0.75 is Option B answer I am sure
Answer:
100.223°C is the boiling point of an aqueous solution.
Explanation:
Osmotic pressure of the solution = π = 10.50 atm
Temperature of the solution =T= 25 °C = 298 .15 K
Concentration of the solution = c
van'y Hoff factor = i = 1 (non electrolyte)


c = 0.429 mol/L = 0.429 mol/kg = m
(density of solution is the same as pure water)
m = molality of the solution
Elevation in boiling point = 


T = Boiling point of the pure solvent
= boiling point of the solution
= Molal elevation constant
We have :
(given)
m = 0.429 mol/kg
T = 100° C (water)




100.223°C is the boiling point of an aqueous solution.
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