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vampirchik [111]
3 years ago
6

Which of these is correct?

Chemistry
1 answer:
Viktor [21]3 years ago
5 0

Answer:

1.89 nol Cu(NO3)2

Explanation:

if you calculate it it will be 1.89

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What is the correct scientific notation for 640,000,000? Question 5 options: 6.4X10^8 6.4X10^10 64X10^10 640X10^8
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For very large numbers, it is much more convenient to use scientific notation. To do this, detect first the position of the decimal point. For whole numbers, the decimal point is place implicitly after the very last digit. Then, move this decimal point to the left until you reach to the last digit. In this case, you moved 8 places until you reach 6.4. Because the number is more than 1, the exponent would have a positive sign. Hence, the scientific notation would be 6.4×10⁸.
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4 years ago
Which of the following is an example of a chemical reaction?
nevsk [136]

Answer:

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3 0
3 years ago
PLease HELP How many molecules of CO2 are there in 55 grams of CO2?
Dafna11 [192]
Explanation: By definition there are 6.022×1023 carbon dioxide molecules in a 44.0⋅g mass.
6 0
3 years ago
Read 2 more answers
Enter your answer in the provided box. An industrial chemist introduces 2.0 atm of H2 and 2.0 atm of CO2 into a 1.00−L container
PSYCHO15rus [73]

Answer: 0.0944 gram of H2

Explanation:

Raising the T from 25 C (298 K) to 700 C (973 K) increases the pressure of each gas by:

2.0 atm x (973 K / 298 K) = 6.53 atm

Where

Kc = Kp because the moles of product equals the moles of reactants.

At equilibriuim, the amounts are

P(H2) = 6.53 - x

P(CO2) = 6.53 - x

P(H2O) = x

P(CO) = x

Kc = Kp = .534 = (x)(x) / [(6.53 - x)(6.53 - x)]

Take the square root of each side

(.534)^0.5 = x / (6.53 - x)

x = 0.731 (6.53 - x)

x = 4.77 - 0.731x

1.731x = 4.77

x = 4.77 / 1.731 = 2.76 atm

P(H2) at equilibriuim = 6.53 - 2.76 = 3.77 atm

P(CO2) at equilibrium = 6.53 - 2.76 = 3.77 atm

PV = nRT

n = PV/RT = [(3.77 atm)(1.00 L)] / [(0.08206 L atm/K mol)(973 K)] = 0.0472 mol H2

0.0472 mol H2 x (2.00 g / 1.00 mol) = 0.0944 g

8 0
3 years ago
How are the excited electrons from stage 1 used in stage 2 of photosynthesis? A. Splitting of water b. Carbon fixation c. Format
Gnom [1K]

Answer;

D. Formation of NADPH

Explanation;

During the process of photosynthesis light is converted to chemical energy.

During stage 1, Excited electrons that leave the chlorophyll pigments in stage 1 are used. Excited electrons are passed through proteins in the thylakoid membrane like a ball being passed from person to person. H2o molecules split and turn into H+ molecules and O2 gas, then pigments take the electrons from the split water molecules and release O2 into the atmosphere.

During stage 2; electrons from 1st cluster pump H+ ions into the thylakoid membrane through the hydrogen ion pump (protein membrane. Higher concentration of H+ ions inside the thylakoid membrane compared to outside. H+ ions diffuse out of the thylakoid throught the ATP synthase (enzyme in membrane). ATP synthase catalyzes the reaction ADP + P ---->ATP.

Stage 2; Excited electrons + H+ ions + NADP+= NADPH

6 0
3 years ago
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