Answer:
C. C, because it’s the highest of all four and C is 2,5 which is medium but the highest one.
The combustion of 30.0 g of glucose at room temperature and pressure produces 24.0 L of carbon dioxide.
<h3>What is combustion?</h3>
It is a reaction in which a substance burns with oxygen to form carbon dioxide and water.
Let's consider the combustion of glucose.
C₆H₁₂O₆ + 6 O₂ ⇒ 6 CO₂ + 6 H₂O
First, let's convert 30.0 g of glucose to moles using its molar mass.
30.0 g × 1 mol/180.16 g = 0.167 mol
The molar ratio of C₆H₁₂O₆ to CO₂ is 1:6. The moles of carbon dioxide produced are:
0.167 mol Glucose × (6 mol CO₂/1 mol Glucose) = 1.00 mol CO₂
1 mol of an ideal gas at room temperature and pressure occupies 24.0 L.
The combustion of 30.0 g of glucose at room temperature and pressure produces 24.0 L of carbon dioxide.
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The symbol of the radioactive nuclide, given the data is ⁴⁰₁₉K
<h3>Data obtained from the question</h3>
- Atomic number = 19
- Mass number = 40
- Symbol of nuclide =?
<h3>How to determine the nuclide</h3>
From the question given above, the atomic number of the nuclide is 19.
Comparing the atomic number (i.e 19) of the nuclide with those in the periodic table, the nuclide is potassium with a symbol of K
<h3>How to determine the symbol of the nuclide</h3>
- Atomic number (Z) = 19
- Mass number (A) = 40
- Name of nuclide = Potassium (K)
- Symbol of nuclide =?
The symbol of a nuclide is given as ᴬ₂X
Where
- A is the mass number
- Z is the atomic number
- X is the symbol of the element
Thus,
ᴬ₂X => ⁴⁰₁₉K
Therefore, the symbol of the nuclide is ⁴⁰₁₉K
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NO.OF.MOLES= MASS/ATOMIC MASS
THE ATOMICITY OF SULPHUR IS 8 AND ITS MASS NUMBER IS 32.
SO, THE ATOMIC MASS IS 256
NO.OF.MOLES= 53.7/256
= 537/2560
= 0.2097
We balance the given reactions above by following the rules in balancing redox reactions in acidic or basic solutions. Balance the atoms aside from the O and H atoms. Then we balance the Os and Hs by adding H2O or H+. Finally, we balance the total charge of the reactant and product by adding e-. We do as follows:
<span>A) H2O2 + Fe 2+ ---> Fe 3+ + H2O (in the acidic solution)
</span><span> 2H+ + </span>H2O2 + Fe 2+ ---> Fe 3+ + 2H2O
e- + 2H+ + H2O2 + Fe 2+ ---> Fe 3+ + 2H2O
<span>
C) CN- + MnO4- ---> CNO- +MnO2 (in basic solution)
</span> CN- + MnO4- ---> CNO- +MnO2 + H2O
2H+ + CN- + MnO4- ---> CNO- +MnO2 + H2O
2OH- + 2H+ + CN- + MnO4- ---> CNO- +MnO2 + H2O + 2OH-
2H2O + CN- + MnO4- ---> CNO- +MnO2 + H2O + 2OH-
e- + H2O + CN- + MnO4- ---> CNO- +MnO2 + 2OH-
<span>
E) S2O2/3- + I2 ---> I- + S4O2/6- (in acidic solution)
2</span>S2O2/3- + I2 ---> 2I- + S4O2/6-
4H+ + 2S2O2/3- + I2 ---> 2I- + S4O2/6- + 2H2O
6e- + 4H+ + 2S2O2/3- + I2 ---> 2I- + S4O2/6- + 2H2O
