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beks73 [17]
4 years ago
6

Which law is known as the law of action-reaction

Chemistry
2 answers:
kakasveta [241]4 years ago
6 0

Answer:

Newton's third law

Explanation:

The law of action-reaction (Newton's third law) explains the nature of the forces between the two interacting objects. According to the law, the force exerted by object 1 upon object 2 is equal in magnitude and opposite in direction to the force exerted by object 2 upon object 1.

shusha [124]4 years ago
6 0

Answer:

The law that relates action to reaction is the Newton's third law of motion.

Explanation:

Newton's third law of motion states that for every action there is an equal and opposite reaction.

Action-reaction force pairs make it possible for fishes to swim, birds to fly, cars to move etc,

Furthermore, take for example, While driving down the road, a firefly strikes the windshield of a car (Action) and makes a quite obvious mess in front of the face of the driver (Reaction) i.e The firefly hit the car and the car hits the firefly.

The statement above means that in every interaction, there is a pair of forces acting on the two interacting objects in this case, the car and fly. The size of the force on the car equals the size of the force on the fly. These two forces are called action and reaction forces and are the subject of Newton's third law of motion.

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Explanation:

How many grams Argon in 1 mol? The answer is 39.948. We assume you are converting between grams Argon and mole. You can view more details on each measurement unit: molecular weight of Argon or mol The molecular formula for Argon is Ar.

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3. What mass of copper could be deposited from a copper(II) Sulphate solution using a current of 5.0 A over 100 seconds? ( F =96
arsen [322]

Mass of copper : 0.165 g

<h3>Further explanation</h3>

Given

5.0 A over 100 seconds

Required

Mass of copper

Solution

Faraday's law:

<em>The mass of the substance formed at each electrode is proportional to the electric current flowing in the electrolysis</em>

<em />\tt W=\dfrac{e.i.t}{96500}<em />

e = Ar / valence = eqivalent weight

i = current

t = time

W = weight

CuSO₄ ----> Cu²⁺ + SO₄²⁻

Cu ----> Cu²⁺ + 2e

e = Ar/2

= 63,5/2 = 31,75

\tt W=\dfrac{31.75\times 5\times 100}{96500}=0.165~g

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