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harina [27]
3 years ago
7

A 2-column table with 10 rows. Column 1 is labeled Classes with entries Hall, Benny, Leggo, Talle, Flower, Gomez, Range, Book, T

oledo, Rich. Column 2 is labeled Watch News with entries 35, 45, 26, 32, 46, 38, 39, 40, 26, 72.
Carol did a study to look at the number of television viewers who watched nightly news in various classes in her school. The results are shown in the table.

Find each listed value.

Range =
Outlier =
Median =
Lower quartile and upper quartile =
Interquartile range =
Mathematics
1 answer:
avanturin [10]3 years ago
6 0
Sorry I forgot what range is but the other are:
Outlier:72
Median: 38.5
Lower and upper quartile: 26,72
Interquartile Range:13
Hope this helps :)
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Find the distance between the points (3,0) and (-1,-5)
nadya68 [22]

Answer:

6.4

Step-by-step explanation:

distance formula \sqrt{(x2-x1)^2+(y2-y1)^2}

\sqrt{(-1-3)^2+(-5-0)^2}

\sqrt{(-4)^2+(-5)^2}

\sqrt{16+25}

\sqrt{41}≈6.403.......

ik it doesnt make any sinse but hope this helps

7 0
3 years ago
Please answer the questions below.
hoa [83]

Answer:

if give brainliest i will answer

Step-by-step explanation:

7 0
2 years ago
A real estate agent has 19 properties that she shows. She feels that there is a 30% chance of selling any one property during a
netineya [11]

Answer:

P(X \geq 5)=1-P(X

We can find the individual probabilities:

P(X=0)=(19C0)(0.3)^0 (1-0.3)^{19-0}=0.00114

P(X=1)=(19C1)(0.3)^1 (1-0.3)^{19-1}=0.0092

P(X=2)=(19C2)(0.3)^2 (1-0.3)^{19-2}=0.0358

P(X=3)=(19C3)(0.3)^3 (1-0.3)^{19-3}=0.0869

P(X=4)=(19C4)(0.3)^4 (1-0.3)^{19-4}=0.1491

And replacing we got:

P(X \geq 5) = 1-[0.00114+0.009282+0.0358+0.0869+0.149]= 0.7178

Step-by-step explanation:

Previous concepts

The binomial distribution is a "DISCRETE probability distribution that summarizes the probability that a value will take one of two independent values under a given set of parameters. The assumptions for the binomial distribution are that there is only one outcome for each trial, each trial has the same probability of success, and each trial is mutually exclusive, or independent of each other".

Solution to the problem

Let X the random variable of interest, on this case we now that:

X \sim Binom(n=19, p=0.3)

The probability mass function for the Binomial distribution is given as:

P(X)=(nCx)(p)^x (1-p)^{n-x}

Where (nCx) means combinatory and it's given by this formula:

nCx=\frac{n!}{(n-x)! x!}

And we want to find this probability:

P(X \geq 5)

And we can use the complement rule:

P(X \geq 5)=1-P(X

We can find the individual probabilities:

P(X=0)=(19C0)(0.3)^0 (1-0.3)^{19-0}=0.00114

P(X=1)=(19C1)(0.3)^1 (1-0.3)^{19-1}=0.0092

P(X=2)=(19C2)(0.3)^2 (1-0.3)^{19-2}=0.0358

P(X=3)=(19C3)(0.3)^3 (1-0.3)^{19-3}=0.0869

P(X=4)=(19C4)(0.3)^4 (1-0.3)^{19-4}=0.1491

And replacing we got:

P(X \geq 5) = 1-[0.00114+0.009282+0.0358+0.0869+0.149]= 0.7178

4 0
3 years ago
Janice is standing 15m form the base of a building. From the point where she is standing, the angle of elevation of the top of t
Alenkasestr [34]

Answer:

the building is 28m

Step-by-step explanation:

3 0
3 years ago
A total of 150 new recruits join an army training course. After one month, 30 have dropped out. what is the percentage decrease
Pachacha [2.7K]
So what will it be a percentage of? it will be the percentage of the original recruits, of the original 150.

for this, we need to divide the number of recruits that left over all recruits, and multiply by 100%:\frac{30}{150} *100%= \frac{1}{5} *100%=20%

so the number of trainees decreased by 20 %
4 0
3 years ago
Read 2 more answers
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