All categories

3 years ago

Determine whether the given function is a solution to the given differential equation.

Mathematics

1 answer:

Anarel [89]3 years ago

5 0

Answer:

It is only 1 and 2 that is the solution to the differential equation

Step-by-step explanation:

1. x''=- 2 Cos t+ 3 sin t and x=2 cos t -3 sin t the addition give 0

2. d^2y/dx^2=- Sin x +2 and y =Sin x +x^2 the addition =x^2+2

but

3. dx/dt= -2 Sin 2t and tx =t Cos 2t =t( 2Cos t - 2 Sin t) the addition it can't equal Sin 2t

You might be interested in

In the figure below, abc is a right triangle. a + b = 150 degrees, and c + d = 35 degrees

timurjin [86]

Um i would need more details
But i thing you would add those together

6 0

3 years ago

Polygon ABCD has the following vertices:

yKpoI14uk [10]

9514 1404 393

Answer:

(b) 38.5

Step-by-step explanation:

The polygon is a trapezoid with bases 4 and 7 and height 7. Its area is given by the formula ...

A = (1/2)(b1 +b2)h

A = (1/2)(4 +7)(7) = 77/2

A = 38.5 . . . . square units

8 0

2 years ago

If there are 360 grams of radioactive material with a half-life of 8 hours, how much of the radioactive material will be left af

lyudmila [28]

Answer:

There will be 22.5 grams left after 32 hours.

Step-by-step explanation:

A half-life is how long it takes for half of the amount to go away. In this case, we see that we have two half-life periods worth, which you can determine by dividing the total time by the half-life time.

32hrs/8hrs = 4 half lives.

Now we can raise 1/2 to the power of how many half lives we have (2). Then we multiply that by the amount in the sample.

(1/2)^4 * 360

1/16 * 360

22.5 grams

And this is an exponential function.

4 0

2 years ago

Read 2 more answers

45 divided by 2531 HELP IDK HOW TO DO THIS.

SpyIntel [72]

0.017779534 because you just divide it

3 0

3 years ago

e) Given the following: Let X = {1, 2, 3, 4) and a relation R on X as R= {(1,2), (2,3), (3,4)}. Find the reflexive and transitiv

Naddika [18.5K]

Answer:

The answer is $\{(1,1),(2,2),(3,3),(4,4),(1,2)(2,3)(3,4),(1,3),(1,4)\}$

Step-by-step explanation:

Remember that a reflexive relation $R\subset \mathcal{P}(X)$ , where $\mathcal{P}(X)$ is the power set of $X$ , is one which conteins the ordered pairs of the form $(a,a)$ , for $a\in X$ .

So, As the reflexive and transitive closure of $R$ (that we will denote by $\overline{R}$ ) is in particular reflexive, we must add to $R$ the elements $\{(1,1) , (2,2),(3,3),(4,4) \}$

A transitive relation $R$ is one in which if the pair $(a,b)$ and the pair $(b,c)$ are in there, then the pair $(a,c)$ must be there too.

So, to complete the relation $R$ to be reflexive and transitive we must add the pair $(1,3)$ (because $(1,2),(2,3)$ are in $R$ ), the pair $(2,4)$ , and the pair $(1,4)$ because we added the pair $(2,4)$ .

Therfore we have that $\overline{R}=\{(1,1),(2,2),(3,3),(4,4),(1,2)(2,3)(3,4),(1,3),(1,4)\}$ .

6 0

3 years ago