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mash [69]
3 years ago
9

How would your experimental formula of magnesium chloride “MgClx” have been affected if

Chemistry
1 answer:
aksik [14]3 years ago
6 0
The compound is used in medicine as a source of magnesium ions, which are essential for many cellular activities. Magnesium chloride has also been used as a cathartic and in alloys. To low
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A student conducts an experiment to determine the effect of adding salt on the boiling temperature of water. The results are sho
sineoko [7]

Answer:

The answer to your question is: The first option is correct.

Explanation:

From the data given, we conclude that as the amount of salt increases, the boiling point of water increases.

Options

If salt is added to water, the water will boil at a higher temperature This is the hypothesis for the experiment.

Salt makes water boil. This statement is not true.

If water is boiling, it must have salt added to it. This statement is incorrect, it is not the goal of the experiment.

If salt is added to water, the water will get cloudy There is not evidence of that from the information given.

3 0
3 years ago
Read 2 more answers
Consider the four free body diagrams. Free-body diagrams are diagrams used to show the relative magnitude and direction of all f
9966 [12]
If you look closely at each of the four diagrams you would be able to conclude that

<span>D) 
Yes. In B and D. In both cases, there is a net force. 
In B, there is a net force to the left; in D there is a net force upward.

In A and C, the forces are in equilibrium both in the horizontal and vertical direction.</span>
5 0
3 years ago
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A horizontal pipe 15 cm in diameter and 4 m long is buried in the earth at a depth of 20 cm. The pipe-wall temperature is 75 deg
Basile [38]

Explanation:

The given data for case (1) is as follows.

  h = 20 cm = 0.2 m

Assuming that a rectangular slab is placed above the pipe and we will calculate the heat transfer as follows.

              Q = kA \frac{\Delta T}{L}

  where,    A = area

                  L = length

                  k = thermal conductivity = 0.8 W/m

             \Delta T = change in temperature.

Therefore, putting the given values into the above formula as follows.

            Q = kA \frac{\Delta T}{L}

                = 0.8 W/m \times (4 m \times 0.15 m) \frac{75 - 5}{0.2}

                = 168 W

For case (2), h = 180 cm = 1.8 m

Therefore, heat lost will be calculated as follows.

                       Q = kA \frac{\Delta T}{L}

                           = 0.8 W/m \times (4 m \times 0.15 m) \frac{75 - 5}{1.8}

                           = 18.67 W

Thus, we can conclude that 18.67 W heat lost if the pipe was buried at a depth of 180 cm.

8 0
3 years ago
You are driving your vehicle through a busy intersection. A vehicle drives across your path. You cannot avoid crashing into the
SVETLANKA909090 [29]

my teacher call it bb you beep and brace for impact

3 0
2 years ago
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Bromine is less electronegative than chlorine, yet methyl bromide and methyl chloride have very similar dipole moments. why? sel
diamong [38]
Bromine is less electronegative than chlorine, yet methyl bromide and methyl chloride have very similar dipole moments. This is because the bond distance in methyl bromide is more due to the large size of bromine atom.
Dipole moment is calculated by multiplying the charge on the atom with the bond distance.
4 0
3 years ago
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