The 2 hormones are insulin & glucagon.
A hormone will only act on a part of the body it 'fits'. A hormone can be thought of as a key, and its target site ( i.e an organ) has specially shaped locks on the cell walls.
If the hormone fits, then it will work.
The hormone can set off a cascade of other singling pathways in the cell to cause an immediate effect ( for instance, insulin signaling leads to a rapid uptake of glucose in muscle cells)
The endocrine system is a tightly regulated system that keeps the hormones and their effects at just the right level. One way this is achieved is through ' feedback loops'. The release of hormones is regulated by other hormones, proteins or neuronal signals.
The released hormone then has its effect on other organs. This effect on the organ feeds back to the original signal to control any further hormone release.
btw- found all this info @ the Better Health channel, an australian government health website , so if your still confused by my answer, check out this website
www.betterhealth.vic.gov.au/health/conditionsandtreatments/hormonal-endocrine-system
Answer:
= 7.57 × 104
(scientific notation)
= 7.57e4
(scientific e notation)
= 75.7 × 103
(engineering notation)
(thousand; prefix kilo- (k))
Explanation:
Just in case this is all of them
Cryo-EM is used to preserve and characterize cycled positive electrodes. Under regular cycling conditions, there isn't an intimate coating layer like CEI.A small electrical short can cause a stable conformal CEI to form in place. The conformal CEI's chemistry is revealed by EELS and cryo-(S)TEM.
It has been assumed that the intimate coating layer generated on the positive electrode, known as cathode electrolyte interphase (CEI), is crucial. However, there are still numerous questions about CEI. This results from the absence of useful instruments to evaluate the chemical and structural characteristics of these delicate interphases at the nanoscale. Here, using cryogenic electron microscopy, we establish a methodology to maintain the natural condition and directly see the interface on the positive electrode.
Learn more about Cathode electrolyte interphase here:
brainly.com/question/861659
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<u>Answer:</u> The energy released in the given nuclear reaction is 1.3106 MeV.
<u>Explanation:</u>
For the given nuclear reaction:
We are given:
Mass of 
= 39.963998 u
Mass of 
= 39.962591 u
To calculate the mass defect, we use the equation:
Putting values in above equation, we get:
To calculate the energy released, we use the equation:
(Conversion factor: 
)
Hence, the energy released in the given nuclear reaction is 1.3106 MeV.
