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8_murik_8 [283]

4 years ago

5

HNO3 is a Bronsted-Lowry acid. What will this substance form when it donates a proton?

1 answer:

Andreas93 [3]4 years ago

7 0

The HNO3 is considered to be a Bronsted - Lowry acid, when this substance 'HNO3', will donate a proton, then it will form another substance. It will form two substances when the proton is donated in the water molecule. The two substances that will be formed is a nitrate iron and a hydronium ion.

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C3H2 + 502 + 3 CO2 + 4H20

nordsb [41]

Answer: 6.2 moles

Explanation:

C3H8(g) + 5O2(g) ---> 3CO2(g) + 4H2O(g)

The balanced equation above shows the combustion of propane, C3H8 in oxygen, O2 to yield carbon dioxide, CO2 and water, H2O

The mole ratio of combustion are as follows:

1 mole of C3H8 react to produce 4 moles of H2O

1.55 mole of C3H8 will react to produce Z moles of H2O

To get the value of Z, cross multiply

Z x 1 mole = 1.55 mole x 4 mole

Z = 6.2 moles

Thus, 6.2 moles of water will be produced from 1.55 moles of propane

6 0

4 years ago

What is the name of this compound?<br> OCH3CCH2 CH3

ELEN [110]

Simple really, when you...

7 0

3 years ago

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Someone help me plz :))) brainliest

SOVA2 [1]

Answer:

Option 2

Explanation:

3 0

3 years ago

How many atoms are present in 0.35 mol of carbon dioxide?

STatiana [176]

0.35 moles carbon dioxide (6.022 X 10^23/1 mole CO2) = 2.1 X 10^23 atoms of
<span> carbon dioxide </span>

6 0

3 years ago

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In a chemical reaction, sulfur (S8) combines with copper to give a pure compound. If you start with 1.000 g of sulfur (S8) and o

Airida [17]

<u>Answer:</u> The empirical formula for the given compound is $Cu_2S$

<u>Explanation:</u>

We are given:

Mass of pure compound containing copper and sulfur = 4.963 g

Mass of S = 1.000 g

Mass of Cu = (4.963 - 1.000) g = 3.963 g

To formulate the empirical formula, we need to follow some steps:

<u>Step 1:</u> Converting the given masses into moles.

Moles of Copper = $\frac{\text{Given mass of Copper}}{\text{Molar mass of Copper}}=\frac{3.963g}{63.55g/mole}=0.0624moles$

Moles of Sulfur = $\frac{\text{Given mass of Sulfur}}{\text{Molar mass of Sulfur}}=\frac{1.000g}{32g/mole}=0.0312moles$

<u>Step 2:</u> Calculating the mole ratio of the given elements.

For the mole ratio, we divide each value of the moles by the smallest number of moles calculated which is 0.0312 moles.

For Copper = $\frac{0.0624}{0.0312}=2$

For Sulfur = $\frac{0.0312}{0.0312}=1$

<u>Step 3:</u> Taking the mole ratio as their subscripts.

The ratio of Cu : S = 2 : 1

Hence, the empirical formula for the given compound is $Cu_2S$

8 0

3 years ago