Answer:
The answer to your question is below
Explanation:
There are 4 laws of gases
- Charles

- Gay Lussac

- Boyle - Mariotte
P1V1 = P2V2
- General law of gases

Let's use these formulas to answer the question
p2 = V2/P1 This is not a law of gases
p1= V1/k This formula is similar to Boyle mariotte equation
but is not.
V2 = k/P2 This equation is correct is Boyle Mariotte formula
V2 = P1V1/ P2 This equation is also correct is Boyle Mariotte formula
V1 = P1/P2 (V2) This equation is incorrect
P2 = (P1) V1/V2 This equation is correct is Boyle mariotte formula
A solid dissolves in a liquid when it mixes completely with the liquid. ... Things which dissolve are called solutes and the liquid in which they dissolve is called a solvent to form a solution
Answer:
the degree of ionization in water is high
Explanation:
The term pH is defined as the negative logarithm of hydrogen ion concentration.
Hence;
pH = -log[H^+]
The pH scale shows the degree of acidity or alkalinity of a solution. A solution of pH 1 is a strong acid. A strong acid dissociates completely in solution.
Hence, acid U has a high degree of ionization in water.
Answer : The pH of buffer is 9.06.
Explanation : Given,

Concentration of HBrO = 0.34 M
Concentration of KBrO = 0.89 M
Now we have to calculate the pH of buffer.
Using Henderson Hesselbach equation :
![pH=pK_a+\log \frac{[Salt]}{[Acid]}](https://tex.z-dn.net/?f=pH%3DpK_a%2B%5Clog%20%5Cfrac%7B%5BSalt%5D%7D%7B%5BAcid%5D%7D)
![pH=pK_a+\log \frac{[KBrO]}{[HBrO]}](https://tex.z-dn.net/?f=pH%3DpK_a%2B%5Clog%20%5Cfrac%7B%5BKBrO%5D%7D%7B%5BHBrO%5D%7D)
Now put all the given values in this expression, we get:


Therefore, the pH of buffer is 9.06.