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nexus9112 [7]
3 years ago
10

Which is a component of John Dalton’s atomic theory?

Chemistry
2 answers:
saul85 [17]3 years ago
8 0
C, he stated that if you broke down atoms further, they would no longer maintain its characteristics
krek1111 [17]3 years ago
3 0

Answer;

C. An atom is a small particle that cannot be broken down

Explanation;

Dalton's atomic theory proposed that all matter was composed of atoms, indivisible and indestructible building blocks. While all atoms of an element were identical, different elements had atoms of differing size and mass.

Dalton’s atomic theory also stated that all compounds were composed of combinations of these atoms in defined ratios.

Dalton also postulated that chemical reactions resulted in the rearrangement of the reacting atoms.

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You would use a Graduated Cylinder
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3 years ago
A solution of phosphoric acid was made by dissolving 10.0 g of H3PO4 in 100.0 mL of water. The resulting volume was 113 mL. Calc
rodikova [14]

Explanation:

Mass of solute = 10.0 g

mass of solvent(water) = m

Volume of solvent( water) = v = 100.0 mL

Density of water= d = 1 g/cm^3=1 g/mL

1 mL= 1 cm^3

m=d\times v=1.0 g/mL\times 100.0 = 100.0 g

Mass of solution(M) = Mass of solute + mass of solvent

M = 10.0 g + 100.0 g = 110.0 g

Volume of the solution = V = 113 mL

Density of the solution = D

D=\frac{M}{V}=\frac{110.0 g}{113 mL}=0.9734 g/mL

The density of the solution is 0.9734 g/ml.

Moles of phosphoric acid = n_1=\frac{10.0 g}{98 g/mol}=0.1020 mol

Moles of water  = n_2=\frac{100.0 g}{18g/mol}=5.556 mol

Mole fraction of phosphoric acid =\chi_1

\chi_1=\frac{n_1}{n_1+n_2}=\frac{0.1020 mol}{0.1020 mol+5.556 mol}

\chi_1=0.01803

Mole fraction of water =\chi_2

\chi_2=\frac{n_2}{n_1+n_2}=\frac{5.556 mol}{0.1020 mol+5.556 mol}

\chi_2=0.9820

[Molarity]=\frac{\text{Moles of solute}}{\text{Volume of solution(L)}}

Moles of  phosphoric acid = 0.1020 mol

Volume of the solution = V = 113 mL = 0.113 L ( 1 mL = 0.001 L)

Molarity of the solution :

=\frac{0.1020 mol}{0.113 L}=0.903 M

[Molality]=\frac{\text{Moles of solute}}{\text{Mass of solvent(kg)}}

Moles of  phosphoric acid = 0.1020 mol

Mass of solvent(water) = m =100.0 g = 0.100 kg ( 1 g = 0.001 kg)

Molality of the solution :

=\frac{0.1020 mol}{0.100 kg}=1.02 mol/kg

6 0
3 years ago
What is amplitude?
NISA [10]

What is amplitude?

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