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Juli2301 [7.4K]
4 years ago
7

Under which condition is competition among fish most likely? A when there are fewer fish in the habitat B when amount of availab

le plankton is greatly reduced C when there is adequate oxygen dissolved in the water D when there is abundant rainfall in the area
Chemistry
2 answers:
MrMuchimi4 years ago
5 0
B when the amount of available plankton is greatly reduced.  This would increase fighting among fish for food.
zlopas [31]4 years ago
3 0

when amount of available plankton is greatly reducrd


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Considering a reaction:
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The rate equation may be described as:
r = -k[A]ⁿ
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ln(r) = -nln([A]) + ln(k)
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Which is classified as an inner transition element
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How many moles of aluminum are needed to make 9 moles of molecular hydrogen? Given the reaction: 2 Al + 6 HCl → 2 AlCl3 + 3H2
VMariaS [17]

Answer:

We need 6.0 moles of aluminium

Explanation:

Step 1: Data given

Number of moles of H2 = 9.0 moles

Step 2: The balanced equation

2 Al + 6 HCl → 2 AlCl3 + 3H2

Step 3: Calculate moles Al

For 2 moles Aluminium, we need 6 moles HCl to produce 2 moles AlCl3 and 3 moles H2

For 9.0 moles of H2 we need 2/3 * 9.0 = 6.0 moles of aluminium

We need 6.0 moles of aluminium

6 0
3 years ago
Helium is the lightest noble gas and the second most abundant element (after hydrogen) in the universe. The mass of a helium−4 a
dmitriy555 [2]

<u>Answer:</u> The fraction of atom's mass contributed by nucleus is 0.99

<u>Explanation:</u>

Nucleons are defined as the sub-atomic particles which are present in the nucleus of an atom. Nucleons are protons and neutrons.

The isotopic symbol of Helium-4 atom is _2^4\textrm{He}

Number of electrons = 2

Number of protons = 2

Number of neutrons = 4 - 2 = 2

We are given:

Mass of He-4 atom = 6.64648\times 10^{-24}g

Mass of 1 electron = 9.10939\times 10^{-28}g

Calculating the mass contributed by the nucleus = m_{He}-2(m_e)

Mass of the nucleus of He-4 atom = 6.64648\times 10^{-24}-(2\times (9.10939\times 10^{-28}))=(6.64648-0.0018219)\times 10^{-24}=6.64466\times 10^{-24}

To calculate the fraction of atom's mass contributed by the nucleus, we use the equation:

\text{Fraction of atom's mass contributed by nucleus}=\frac{\text{Mass of nucleus}}{\text{Mass of atom}}

Putting values in above equation, we get:

\text{Fraction of atom's mass contributed by nucleus}=\frac{6.64466\times 10^{-24}g}{6.64648\times 10^{-24}g}=0.99

Hence, the fraction of atom's mass contributed by nucleus is 0.99

8 0
3 years ago
(pls help)
WITCHER [35]
Anthony’s because it explains way more
8 0
2 years ago
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